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kherson [118]
1 year ago
6

What fraction of the original uranium-235 should be left after 3.5 billion years?

Chemistry
1 answer:
ANEK [815]1 year ago
3 0

1/3 fraction of the original uranium-235 should be left after 3.5 billion years

The only naturally occurring isotope of this radioactive metal, uranium-235, is capable of supporting a nuclear fission reaction, making it special. A variation of an element called an isotope has a different number of neutrons in its nucleus. Approximately 93.5 percent of the uranium used in modern nuclear bombs is enriched.

On average, plutonium-239 makes up 93% or more of nuclear bombs, whereas plutonium-240 makes up less than 7% and other plutonium isotopes are present in extremely minute amounts. A nuclear bomb requires around 33 pounds (15 kilograms) of enriched uranium to function, according to the Union of Concerned Scientists.

To learn more about uranium please visit-
brainly.com/question/9099776
#SPJ4

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Hello this is my 3 attempt, please someone answer this i'm begging you.
denis23 [38]

Answer:

Explanation:

No worries, I got you :)

So for the first question, you need to use PV=nRT to find the n, or in other words, the number of moles. Then, you can find the molar mass since you know the grams and the moles

110 kPa / 101.3 = 1.085 atm (I converted it to atm so I can use the .08206 L atm/ k mol  for the rate)

550 ml / 1000 = .550 L (I converted mL to L in order to use the .08206 L atm/ k mol for the Rate)

28.5 c + 273 = 301.5 K (I converted C to K in order to use the .08206 L atm/ k mol for the Rate)

PV=nRT

(1.085) (.550 L) = n (0.08206) (301.5)

Divide the (0.08206) (301.5) to get n alone:

(1.085) (.550 L) / (0.08206) (301.5) = n

When I divided, I got n= .02412 moles, and since we have 1.88g , we divide the 1.88 by .02412 to get the molar mass (grams/mole)

77.94 g/mole is the molar mass

we know that there are 3 H's in the compound, so we do 3(1.008) and subtract 77.94 by what you get.

3 x 1.008 = 3.024 -----> 77.94-3.024 = 74.9

Now we look at the periodic table and try to find an element that has a molar mass of 74.9

Arsenic (As) has a molar mass of 74.922, which is close enough. Plus, Arsenic has a charge of 3, so it fits with the 3 hydrogens.

5 0
3 years ago
If boron atoms have 5 electrons, how many electrons are in the outer electron shell of a boron atom?
ANEK [815]

Answer:

3

Explanation:

The first election shell can only hold 2 electrons, but the next one can hold up to 8

3 0
2 years ago
How many grams are in 4.5 moles of Li20
Rzqust [24]

134.5 grams in 4.5 moles of Li2O (lithium oxide).

3 0
3 years ago
(My losing emote at the top..)
forsale [732]

Answer:

neutral charge

I hope it's helps you

4 0
3 years ago
Read 2 more answers
Can you pls tell me the net ironic equation of H₂²⁺(aq) + O₂²⁻(aq) + Mg²⁺(aq) + SO₃²⁻(aq) → Mg²⁺(aq)+SO²⁻₄(aq) + H₂O(l)
almond37 [142]

Answer:

H₂²⁺(aq) + O₂²⁻(aq) + SO₃²⁻(aq) → SO²⁻₄(aq) + H₂O(l)

Explanation:

H₂²⁺(aq) + O₂²⁻(aq) + Mg²⁺(aq) + SO₃²⁻(aq) → Mg²⁺(aq) + SO²⁻₄(aq) + H₂O(l)

A careful observation of the equation above, shows that the equation is already balanced.

To obtain the net ionic equation, we simply cancel Mg²⁺ from both side of the equation as shown below:

H₂²⁺(aq) + O₂²⁻(aq) + SO₃²⁻(aq) → SO²⁻₄(aq) + H₂O(l)

5 0
3 years ago
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