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3 years ago

Why is the Copernican Revolution significant? Check all that apply.

Physics

2 answers:

k0ka [10]3 years ago

6 0

Answer:

2.Scientists discovered new evidence to support their theories.

3.Scientists discovered that old interpretations of data was incorrect.

4.Scientists used observations and mathematical data to solve problems in new ways.

Explanation: Here you go

Scilla [17]3 years ago

6 0

Answer:

B. Scientists discovered new evidence to support their theories.

C. Scientists discovered that old interpretations of data was incorrect.

D. Scientists used observations and mathematical data to solve problems in new ways.

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Estimate the Joule-Thomson coefficient of refrigerant-134a at 0.70 MPa and 50°C. Assume the second state will be selected for a

leva [86]

Answer:

$\mu = 0.018\,\frac{^{\textdegree}C}{kPa}$

Explanation:

The Joule-Thomson coefficient is the ratio of the change of temperature to the change of pressure under isoenthalpic conditions:

$\mu = \left(\frac{\Delta T}{\Delta P}\right)_{h}$

Initial and final properties are:

$T_{1} = 50^{\textdegree}C, P_{1}=700\,kPa, h_{1}=288.54\,\frac{kJ}{kg}$ . Superheated Vapor.

$T_{2} = 48.186^{\textdegree}C, P_{2}=600\,kPa, h_{2}=288.54\,\frac{kJ}{kg}$ . Superheated Vapor.

The Joule-Thomson coefficient is approximately:

$\mu = \frac{50^{\textdegree}C-48.186^{\textdegree}C}{700\,kPa-600\,kPa}$

$\mu = 0.018\,\frac{^{\textdegree}C}{kPa}$

5 0

4 years ago

Besides ethical considerations, what is another reason why Milgram’s experiment may be difficult to duplicate?

ki77a [65]

Last month, we featured IRB best practices (“IRBs: Navigating the Maze” November 2007 Observer), and got the ball rolling with strategies and tips that psychological scientists have found to work. Here, we continue the dissemination effort with the second of three articles by researchers who share their experiences with getting their research through IRB hoops. Jerry Burger from Santa Clara University managed to do the seemingly impossible — he conducted a partial replication of the infamous Milgram experiment. Read on for valuable advice, and look for similar coverage in upcoming Observers. These are the first words I said to Muriel Pearson, producer for ABC News’ Primetime, when she approached me with the idea of replicating Stanley Milgram’s famous obedience studies. Milgram’s work was conducted in the early 1960s before the current system of professional guidelines and IRBs was in place. It is often held up as the prototypic example of why we need policies to protect the welfare of research participants. Milgram’s participants were placed in an emotionally excruciating situation in which an experimenter instructed them to continue administering electric shocks to another individual despite hearing that person’s agonizing screams of protest. The studies ignited a debate about the ethical treatment of participants. And the research became, as I often told my students, the study that can never be replicated. Hope this helps!

8 0

3 years ago

(a) The Eskimo pushes the same 50.0-kg sled over level ground with a force of 1.75 102 N exerted horizontally, moving it a dista

vivado [14]

Answer: 0.306

Explanation:

from the question we are given the following

mass of sled (m) = 50 kg

force (f) = 1.75 x 10^2 N = 175 N

distance (s) = 6 m

net work done on the sled = 1.50 x 10 ^2 N = 150 N

acceleration due to gravity (g) = 9.8 m/s^2

coefficient of friction = μ

lets first calculate the frictional force (ff)

ff = μ x m x g = μ x 50 x 9.8 = 490 μ

work done on the slide by the applied force (W1)= f x s = 175 x 6 = 1050 j

work done on the slide by frictional force (W2) = ff x s = 490 μ x 6 = 2940μ j

now the net work done is the work done by the frictional force subtracted from the work done by the applied force

net work done = W1 - W2

150 = 1050 - 2940μ

2940μ = 1050 - 150

μ = 900 / 2940

μ = 0.306

3 0

3 years ago

A gold bar 20.0kg at 35.0°c is placed in a large insulated 0.8kg glass container at 15°c and 2.0kg of water at 25°c.. calculate

Oksanka [162]

Answer:

The final equilibrium temperature is approximately 26.69 °C

Explanation:

The heat transferred, ΔQ, from a hot body to a cold one is given by the following formula;

ΔQ = m·c·ΔT

Where;

m = The mass of the body

c = The specific heat capacity of the body

ΔT = The temperature change of the body

The given mass of the gold bar, m₁ = 20.0 kg

The initial temperature of the gold bar, T₁ = 35.0 °C

The specific heat capacity of gold, c₁ = 0.13 kJ/(kg·K)

The mass of the glass container, m₂ = 0.8 kg

The initial temperature of the glass container, T₂ = 15°C

The specific heat capacity of glass, c₂ = 0.792 kJ/(kg·K)

The mass of the added water, m₃ = 2.0 kg

The initial temperature of the added water, T₃ = 25°C

The specific heat capacity of water, c₃ = 4.2 kJ/(kg·K)

The heat lost by the gold = The heat gained by the glass and the water

Let 'T' represent the temperature at the final equilibrium, we have;

m₁·c₁·ΔT₁ = m₂·c₂·ΔT₂ + m₃·c₃·ΔT₃

Where;

ΔT₁ = T₁ - T

ΔT₂ = T - T₂

ΔT₃ = T - T₃

∴ 20.0 × 0.13 × (35 - T) = 0.8 × 0.792 × (T - 15) + 2.0 × 4.2 × (T - 25)

Expanding and collecting like terms (using a graphing calculator) gives;

91 - 2.6·T = 9.0336·T - 219.504

9.0336·T + 2.6·T = 219.504 + 91 = 310.504

11.6336·T = 310.504

T = 310.504/11.6336 ≈ 26.69

The final equilibrium temperature, T ≈ 26.69 °C.

4 0

3 years ago

HELP PLEASE DUE 3 MINUTES HELP

Elena-2011 [213]

Answer:

Mechanical weathering breaks rocks into smaller pieces without changing their composition. ... Chemical weathering breaks down rocks by forming new minerals that are stable at the Earth's surface. Water, carbon dioxide, and oxygen are important agents of chemical weathering.

Explanation:

8 0

3 years ago