<u><em>The question doesn't provide enough data to be solved, but I'm assuming some magnitudes to help you to solve your own problem</em></u>
Answer:
<em>The maximum height is 0.10 meters</em>
Explanation:
<u>Energy Transformation</u>
It's referred to as the change of one energy from one form to another or others. If we compress a spring and then release it with an object being launched on top of it, all the spring (elastic) potential energy is transformed into kinetic and gravitational energies. When the object stops in the air, all the initial energy is now gravitational potential energy.
If a spring of constant K is compressed a distance x, its potential energy is
![\displaystyle P_E=\frac{Kx^2}{2}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20P_E%3D%5Cfrac%7BKx%5E2%7D%7B2%7D)
When the launched object (mass m) reaches its max height h, all that energy is now gravitational, which is computed as
![U=mgh](https://tex.z-dn.net/?f=U%3Dmgh)
We have then,
![U=P_E](https://tex.z-dn.net/?f=U%3DP_E)
![\displaystyle mgh=\frac{Kx^2}{2}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20mgh%3D%5Cfrac%7BKx%5E2%7D%7B2%7D)
Solving for h
![\displaystyle h=\frac{Kx^2}{2mg}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20h%3D%5Cfrac%7BKx%5E2%7D%7B2mg%7D)
We have little data to work on the problem, so we'll assume some values to answer the question and help to solve the problem at hand
Let's say: x=0.2 m (given), K=100 N/m, m=2 kg
Computing the maximum height
![\displaystyle h=\frac{(100)0.2^2}{2(2)(9.8)}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20h%3D%5Cfrac%7B%28100%290.2%5E2%7D%7B2%282%29%289.8%29%7D)
![\displaystyle h=\frac{4}{39.2}=0,10\ m](https://tex.z-dn.net/?f=%5Cdisplaystyle%20h%3D%5Cfrac%7B4%7D%7B39.2%7D%3D0%2C10%5C%20m)
The maximum height is 0.10 meters
Answer:
0.71121 km/s
Explanation:
= Velocity of planet initially = 54 km/s
= Distance from star = 0.54 AU
= Final velocity of planet
= Final distance from star = 41 AU
As the angular momentum of the system is conserved
![mv_1r_1=mv_2r_2\\\Rightarrow v_1r_1=v_2r_2\\\Rightarrow v_2=\frac{v_1r_1}{r_2}\\\Rightarrow v_2=\frac{54\times 0.54}{41}\\\Rightarrow v_2=0.71121\ km/s](https://tex.z-dn.net/?f=mv_1r_1%3Dmv_2r_2%5C%5C%5CRightarrow%20v_1r_1%3Dv_2r_2%5C%5C%5CRightarrow%20v_2%3D%5Cfrac%7Bv_1r_1%7D%7Br_2%7D%5C%5C%5CRightarrow%20v_2%3D%5Cfrac%7B54%5Ctimes%200.54%7D%7B41%7D%5C%5C%5CRightarrow%20v_2%3D0.71121%5C%20km%2Fs)
When the exoplanet is at its farthest distance from the star the speed is 0.71121 km/s.
The fold was formed from something brittle. Since the syncline doesn't have properties from rock, it would be broken down easily.