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Katarina [22]
3 years ago
11

What is the strength of the electric field 0.020 m from a 12 µC charge?

Physics
1 answer:
Misha Larkins [42]3 years ago
8 0
The answer is 2.7 x 10^8 N/C
You might be interested in
A cart of mass 20 kg, initially at rest, is pushed with a net force of 40 N on a flat surface. If the cart is pushed 5 m, what i
bixtya [17]
Using the theorem of kinetic energy
1/2mVf² - 1/2mVi²= WF + Wp,     Wp=0
WF = F. AB, AB=5m and F= 40N, m=20kg
so the final kinetic  is KEf= 1/2mVf² = WF =<span>F. AB= 40*5=200J
</span>
the final velocity is 1/2mVf² <span>=200, implies   Vf= sqrt(20)=2sqrt(5)m/s</span>

3 0
3 years ago
(7) A 2500 lbm car moving at 25 mi/hr is accelerated at a constant rate of 15 ft/s2 up to a speed of 50 mi/hr. What is the force
balandron [24]

Answer:

The  force is  F =  1164.6\  lbf

The time is   \Delta t =  2.44 \  s

Explanation:

From the question we are told that

  The  mass of the car is  m  =  2500 \ lbm

   The  initial velocity of the car is u  =  25 \ mi/hr

   The final  velocity of the car is  v  =  50 \  mi/hr

  The acceleration is  a =  15 ft/s^2 =  \frac{15 *  3600^2}{ 5280} =  36818.2 \  mi/h^2

   

Generally the acceleration is mathematically represented as

      a =  \frac{v-u}{\Delta t}

=>   36818.2 =  \frac{50 - 25 }{ \Delta t}

=>   t = 0.000679 \  hr

converting to seconds

       \Delta t =  0.0000679 *  3600

=>     \Delta t =  2.44 \  s

Generally the force is mathematically represented as

        F  =  m * a

=>      F  =  2500 *  15

=>      F  =  37500 \ \frac{lbm *  ft}{s^2}

Now converting to foot-pound-second we have  

         F =  \frac{37500}{32.2}

=>        F =  1164.6\  lbf

7 0
3 years ago
8. If the speed of a wave is 1500 m/s and its frequency is 200 Hz, what is the wavelength?
sammy [17]

formula for wavelength = speed/frequency

So 1500/200 = 7.5 meters

4 0
3 years ago
A student conduct an experiment to determine habitation of salt to water affect the density of the water the student feels three
Nikolay [14]
Any like answer choices would be helpful '-'
8 0
3 years ago
A force of 1.00 x 10^2 pounds acts at an angle of 60.0° to the x-axis. (The force is accurate to 3 significant figures.) What ar
tamaranim1 [39]

Answer:

Fx= 50.0 Pounds : Components of the force along the x-axis

Fy= 86.6 Pounds : Component of the force along the y-axis

Explanation:

Conceptual Analysis

To find the components (Fx, Fy) of the total force (F), we apply the trigonometric concepts for a right triangle, where the perpendicular sides of the triangle are the components (Fx, Fy) of the force (F), the hypotenuse (h) is the magnitude of the total force F and β is the angle that forms the horizontal component with the hypotenuse.

Formulas

cos β : x/h  :    x: side adjacent to the β angle  h: hypotenuse  (1)

sin β = y/h  :    y: side opposite to the β angle  h: hypotenuse  (2)

Known Data

Known data

F= 1.00 * 10² pounds  = 100 pounds :  magnitude of total force

β =  60.0° to the x-axis. : Angle that forms the force with the x-axis

Problem Development

We apply the formula 1 to calculate horizontal component (Fx)

cos β :Fx/F

Fx= F cosβ  = 100*cos 60° = 50.0 Pounds

We apply the formula 2 to calculate vertical component (Fy)

sin β = Fy/F

Fy= F sinβ = 100*sin 60° = 86.6 Pounds

6 0
4 years ago
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