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Gala2k [10]
4 years ago
13

What are the steps of determine an inverse of a function?

Mathematics
1 answer:
Yuki888 [10]4 years ago
5 0

Step-by-step explanation:

First, replace f(x) with y . ...

Replace every x with a y and replace every y with an x .

Solve the equation from Step 2 for y . ...

Replace y with f−1(x) f − 1 ( x ) . ...

Verify your work by checking that (f∘f−1)(x)=x ( f ∘ f − 1 ) ( x ) = x and (f−1∘f)(x)=x ( f − 1 ∘ f ) ( x ) = x are both true.

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what is the distance from the origin to the midpoint of the line segment defined by the endpoints (-4, 0) and (2, -2)?
Zielflug [23.3K]
Answer. I hope it helps you !!

5 0
3 years ago
WILL MARK BRAINLIEST AND RATE 5 STARS
insens350 [35]
A) No solutions, because the number under the square root symbol in the quadratic equation (b^2 - 4ac) is negative. 

B) One solutions, because the number under the square root symbol in the quadratic equation (b^2 - 4ac) is equal to 0. 
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4 years ago
Read 2 more answers
Use the tables to complete the statements,
Blababa [14]

Answer:

Short term Capital gain and $1200

Step-by-step explanation:

Any investment held under a year falls under short term capital gain

5,000 X 0.24 = 1,200

6 0
3 years ago
What is the answer please.... need help
mina [271]

Answer:

f\left(x\right)=x^3-6x^2+3x+10 is the function of the least degree has the real coefficients and the leading coefficients of 1 and with the zeros -1, 5, and 2.

Step-by-step explanation:

Given the function

f\left(x\right)=x^3-6x^2+3x+10

As the highest power of the x-variable is 3 with the leading coefficients of 1.

  • So, it is clear that the polynomial function of the least degree has the real coefficients and the leading coefficients of 1.

solving to get the zeros

f\left(x\right)=x^3-6x^2+3x+10

0=x^3-6x^2+3x+10              ∵  f(x)=0

as

Factor\:x^3-6x^2+3x+10\::\:\left(x+1\right)\left(x-2\right)\left(x-5\right)=0

so

\left(x+1\right)\left(x-2\right)\left(x-5\right)=0    

Using the zero factor principle

if  ab=0\:\mathrm{then}\:a=0\:\mathrm{or}\:b=0\:\left(\mathrm{or\:both}\:a=0\:\mathrm{and}\:b=0\right)

x+1=0\quad \mathrm{or}\quad \:x-2=0\quad \mathrm{or}\quad \:x-5=0

x=-1,\:x=2,\:x=5

Therefore, the zeros of the function are:

x=-1,\:x=2,\:x=5

f\left(x\right)=x^3-6x^2+3x+10 is the function of the least degree has the real coefficients and the leading coefficients of 1 and with the zeros -1, 5, and 2.

Therefore, the last option is true.    

8 0
3 years ago
Harper has $15.00 to spend at the grocery store. she is going to buy bags of fruit that cost $4.75 each and one box of crackers
Butoxors [25]
She can buy 2 bags of fruit (adds up to 9.50) and of course the box of crackers that is 3.5, in total it adds to $13. So the answer is she can buy 2 bags of fruit.

6 0
3 years ago
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