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vekshin1
3 years ago
8

Find the value of x

Mathematics
2 answers:
Svet_ta [14]3 years ago
7 0

Answer:

150^o

Step-by-step explanation:

<u>Step 1:  Distribute the plus</u>

<u />(x + 15)^o + (135 - x)^o

x + 15 + 135 - x

<u>Step 2:  Combine like terms</u>

<u />x + 15 + 135 - x

(x - x)^o + (15 + 135)^o

0 + 150^o

150^o

Answer:  150^o

Vedmedyk [2.9K]3 years ago
6 0
The answer is X=2 I used Photomath to make sure

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Your teacher announced a 50 point math quiz
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Answer:

There would be 5, 4 point questions and 10, 3 point answers

Step-by-step explanation:

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3 years ago
Assume that random guesses are made for seven multiple choice questions on an SAT test, so that there are n=7 trials, each with
Vedmedyk [2.9K]

Answer:

P(X < 4) = 0.5

Step-by-step explanation:

For each question, there are only two possible outcomes. Either it is answered correctly, or it is not. The probability of a question being answered correctly is independent of any other question. This means that we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

In this question, we have that:

n = 7, p = 0.5

Find the probability that the number of correct answers is fewer than 4:

This is

P(X < 4) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3)

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{7,0}.(0.5)^{0}.(0.5)^{7} = 0.0078

P(X = 1) = C_{7,1}.(0.5)^{1}.(0.5)^{6} = 0.0547

P(X = 2) = C_{7,2}.(0.5)^{2}.(0.5)^{5} = 0.1641

P(X = 3) = C_{7,3}.(0.5)^{3}.(0.5)^{4} = 0.2734

P(X < 4) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) = 0.0078 + 0.0547 + 0.1641 + 0.2734 = 0.5

So

P(X < 4) = 0.5

6 0
3 years ago
HELPPPPPP!!!!!!!!!!!!!!!
Katarina [22]

Answer:

I might be wrong i think its C but double check and dont put it in until you are sure its right

Step-by-step explanation:

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