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xz_007 [3.2K]
4 years ago
7

A prop for the theater club’s play is constructed as a cone topped with a half-sphere. What is the volume of the prop? Round you

r answer to the nearest tenth of a cubic inch. Use 3.14 to approximate pi.
(The cone has a radius of 8 inches and a height of 12 inches.)
Mathematics
1 answer:
IrinaVladis [17]4 years ago
5 0

Answer:

1875.6 in³

Step-by-step explanation:

(⅓×3.14×8²×12) + (⅔×3.14×8³)

1875.626667 in³

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Answer:

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Step-by-step explanation:

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So, the width is = w-8 inches

Length is = w+12-8=w+4 inches

When we are folding the cut portion, that gives the height as = 4 inches

The volume is given by : length x width x height

And volume is given as 256 cubic inches

So, 256=(w+4)(w-8)(4)

=> 256=(w^{2}-4w-32)4

=> 64=(w^{2}-4w-32)

=> w^{2} -4w=96

or w^{2} -4w-96=0

=> w^{2} -12w+8w-96=0

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We get , (w+8)=0 ; w = -8(neglect the negative value)

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We can check by putting these values in equation : 256=(w+4)(w-8)(4)

256=(12+4)(12-8)(4)

=> 256=(16)(4)(4)

=> 256=256

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