There is a 909 mph gap between the two cars. So if we can divide 3636 by 909 we get 4.
Answer: 4 Hours
Answer:
19
Step-by-step explanation:
Follow PEMDAS
4^2 + 6 ÷ 2
16 + 6 ÷ 2
16 + 3
19
Answer: 0.31 or 31%
Let A be the event that the disease is present in a particular person
Let B be the event that a person tests positive for the disease
The problem asks to find P(A|B), where
P(A|B) = P(B|A)*P(A) / P(B) = (P(B|A)*P(A)) / (P(B|A)*P(A) + P(B|~A)*P(~A))
In other words, the problem asks for the probability that a positive test result will be a true positive.
P(B|A) = 1-0.02 = 0.98 (person tests positive given that they have the disease)
P(A) = 0.009 (probability the disease is present in any particular person)
P(B|~A) = 0.02 (probability a person tests positive given they do not have the disease)
P(~A) = 1-0.009 = 0.991 (probability a particular person does not have the disease)
P(A|B) = (0.98*0.009) / (0.98*0.009 + 0.02*0.991)
= 0.00882 / 0.02864 = 0.30796
*round however you need to but i am leaving it at 0.31 or 31%*
If you found this helpful please mark brainliest
Answer:
y=x+2
Step-by-step explanation:
the standard form is y=mx+b where m is the slope and b is the y intercept
TO FIND THE SLOPE: we take the x and y intercepts as a fraction. in this case the line touches the y axis (vertical) at point/value 2 and the x axis at point 2 as well. This means the slope is 2/2x which can be simplified to 1x or just x.
TO FIND THE Y INTERCEPT: we find where the line touches the y axis at point 2.
the slope is plugged into the m of the equation and the y intercept is plugged into the b of the equation.
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