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bearhunter [10]
4 years ago
5

***********************(((((((((((((((((((((((Can i get some help?())))))))))))))))))))))))))))))))))))))************

Mathematics
1 answer:
Artemon [7]4 years ago
7 0

Answer:

The inter-quartile range is 13.

Step-by-step explanation:

   1. Order the data from least to greatest

   2. Find the median  of the data.

   3. Calculate the median of both the lower and upper half of the data.

   4. The inter-quartile range is the difference between the upper and lower medians.

Lower Median: 17

Media: 25.5

Upper Median: 30

<h2>Inter-quartile range: 30 - 17 = 13</h2>
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spin [16.1K]

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8.5 or 4.25 i think pretty sure its 8.5 tho

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3 years ago
Choose yes or no to tell whether the expression represent a 20% discount off the price of an item that originally cost d dollars
Vaselesa [24]

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Part A: Explain why the x-coordinates of the points where the graphs of the equations
Furkat [3]

A. Answer: It is a system of equations that can be solved using substitution method; x = -3

<u>Step-by-step explanation:</u>

y = 4⁻ˣ

y = 8⁻ˣ⁻¹

Use substitution to replace y in the second equation with 4⁻ˣ

4⁻ˣ = 8⁻ˣ⁻¹

Solve by manipulating the 4 and 8 so they have the same base, then set the exponents equal to each other and solve for x

2²⁽⁻ˣ⁾ = 2³⁽⁻ˣ⁻¹⁾

2(-x) = 3(-x - 1)

-2x = -3x - 3

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Plug the x-value into either of the equations to solve for y

y = 4⁻ˣ

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y = 64

Solution is: (-3, 64)

********************************************************************************************

B.

\begin{array}{c||c}\ \quad \underline{y=4^{-x}\quad} \ &\quad \underline{y=8^{-x-1}}\quad \\\end{array}\\\begin {array}{c|c||c|c}\quad \underline{x} \quad&\quad \underline{y} \quad &\quad \underline{x} \quad&\quad \underline{y} \quad \\ -3&64&-3&64\\&&&\\-2&16&-2&8\\&&&\\-1&4&-1&1\\&&&\\0&1&0&\dfrac{1}{8}\\ &&&\\1&\dfrac{1}{4}&1&\dfrac{1}{64}\\&&&\\2&\dfrac{1}{16}&2&\dfrac{1}{512}\\&&&\\3&\dfrac{1}{64}&3&\dfrac{1}{4096}\\\end{array}

Notice that they share the same x, y-coordinate: (-3, 64)

*******************************************************************************************

C. Answer: Graph both equations to see where they cross

<u>Step-by-step explanation:</u>

see attached graph

4 0
4 years ago
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7 0
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