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bearhunter [10]
3 years ago
5

***********************(((((((((((((((((((((((Can i get some help?())))))))))))))))))))))))))))))))))))))************

Mathematics
1 answer:
Artemon [7]3 years ago
7 0

Answer:

The inter-quartile range is 13.

Step-by-step explanation:

   1. Order the data from least to greatest

   2. Find the median  of the data.

   3. Calculate the median of both the lower and upper half of the data.

   4. The inter-quartile range is the difference between the upper and lower medians.

Lower Median: 17

Media: 25.5

Upper Median: 30

<h2>Inter-quartile range: 30 - 17 = 13</h2>
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The answer is 56.



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When sampling without replacement, the probability of obtaining a certain sample is best given by a:
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Hypergeometric distribution

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What is the solution to -3/4x + 2 is less then or equal to -7
KonstantinChe [14]

QUESTION:

What is the solution to -3/4x + 2 is less then or equal to -7

ANSWER:

\green{{x ≥ 12}}

STEP-BY-STEP EXPLANATION:

First, Simplify each term

Combine {x} and {\frac{3}{4}}

\green{{-\frac{x × 3}{4} + 2 ≤ - 7}}

Move 3 to the left of {x}

\green{{-\frac{3x}{4} + 2 ≤ - 7}}

Second, Move all terms not containing {x} to the right side of the inequality

Subtract 2 from the both sides of the inequality

\green{{-\frac{3x}{4} ≤ - 7 - 2}}

Subtract 2 from - 7

\green{{-\frac{3x}{4} ≤ - 9}}

Third, Multiply each term in {-\frac{3x}{4} ≤ - 9 by - 1}

When multiplying or dividing both sides of an inequality by a negative value, flip the direction of the inequality sign

\green{{-\frac{3x}{4} × - 1 ≥ ( - 9) × - 1}}

Fourth, Multiply {-\frac{3x}{4} × - 1}

Multiply - 1 by - 1

\green{{1\frac{3x}{4} ≥ ( - 9) × - 1}}

Multiply {\frac{3x}{4}} by 1

\green{{\frac{3x}{4} ≥ ( - 9) × 1}}

Multiply - 9 by - 1

\green{{\frac{3x}{4} ≥ 9}}

Multiply both sides of the equation by 4

\green{{3x ≥ 9 × (4)}}

Multiply 9 by 4

\green{{3x ≥ 36}}

Fifth, Divide each term by 3 and simplify

Divide each term in {3x ≥ 36 by 3}

\green{{\frac{3x}{3} ≥ \frac{36}{3}}}

Sixth, Cancel the common factor of 3

Cancel the common factor

\red{{\frac{3x}{3}}} ≥ \green{{\frac{36}{3}}}

Divide {x} by 1

\green{{x ≥ \frac{36}{3}}}

Lastly, Divide 36 by 3

\green{\boxed{x ≥ 12}}

hope it's helps

4 0
3 years ago
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