Answer:
She was president (1892–1900) of the <u>National Woman Suffrage Association</u>.
Practically anything above -8
Such as -7, 2, 15600, anything not under -7.9
We presume your cost function is
c(p) = 124p/((10 +p)(100 -p))
This can be rewritten as
c(p) = (124/11)*(10/(100 -p) -1/(10 +p))
The average value of this function over the interval [50, 55] is given by the integral
![\frac{1}{55-50} \times \frac{-124}{11} \int\limits^{55}_{50} {(\frac{1}{x+10}+\frac{10}{x-100})} \, dx](https://tex.z-dn.net/?f=%20%5Cfrac%7B1%7D%7B55-50%7D%20%5Ctimes%20%5Cfrac%7B-124%7D%7B11%7D%20%5Cint%5Climits%5E%7B55%7D_%7B50%7D%20%7B%28%5Cfrac%7B1%7D%7Bx%2B10%7D%2B%5Cfrac%7B10%7D%7Bx-100%7D%29%7D%20%5C%2C%20dx)
This evaluates to
(-124/55)*(ln(65/60)+10ln(45/50)) ≈ 2.19494
The average cost of removal of 50-55% of pollutants is about
$2.19 hundred thousand = $219,000
8 * 3/4
Multiply 8 by 4 to get 32 then divide 32 by 3 to get 3.6 repeating
3/3 is basically 1 so its still 3.6
3.6 is 3 3/5
-XCalypso
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