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Tanzania [10]
3 years ago
7

You are measuring the height of a statue. You stand 17 feet from the base of the statue. You measure the angle of elevation from

the ground to the top of the statue to be 61º. Find the height h​ of the statue to the nearest foot.
Mathematics
1 answer:
olga_2 [115]3 years ago
6 0

Answer:

height ≈ 31 ft

Step-by-step explanation:

The illustration below will form a right angle triangle. He is standing 17 ft away from the base of the statue.  The angle of elevation from the ground to the top of the statue  is 61°. The height of the statue can be computed below.

adjacent side of the triangle = 17 ft

opposite side = a

Using SOHCAHTOA principle

tan 61° = opposite/adjacent

tan 61° = a/17

cross multiply

a = 17 tan 61°

a = 17 × 1.80404775527

a = 30.6688118396

a ≈ 31 ft

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Let the random variable X be the number of rooms in a randomly chosen owner-occupied housing unit in a certain city. The distrib
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Answer:

a) X is a discrete random variable.

b) 2% probability of choosing a unit with 10 rooms

c) 98% probability that a unit chosen at random is not a 10-room unit

d) 30% probability that a unit chosen at random has less than five rooms

e) 7% probability that a unit chosen at random has less than five rooms

Step-by-step explanation:

The distribution means that:

7% probability that a randomly chosen owner-occupied housing unit in a certain city has 3 rooms.

23% probability that a randomly chosen owner-occupied housing unit in a certain city has 4 rooms.

36% probability that a randomly chosen owner-occupied housing unit in a certain city has 5 rooms.

19% probability that a randomly chosen owner-occupied housing unit in a certain city has 6 rooms.

5% probability that a randomly chosen owner-occupied housing unit in a certain city has 7 rooms.

5% probability that a randomly chosen owner-occupied housing unit in a certain city has 8 rooms.

3% probability that a randomly chosen owner-occupied housing unit in a certain city has 9 rooms.

?% probability that a randomly chosen owner-occupied housing unit in a certain city has 10 rooms.

(a) Is X a discrete or continuous random variable?

X is the number of rooms in a randomly selected house. The number of rooms is a countable variable, that is, only assumes values like 1,2,3,4,... You cannot have 3.5 rooms, for example.

So X is a discrete random variable.

(b) What must be the probability of choosing a unit with 10 rooms?

The sum of all probabilities must be 100%(1 decimal). So

0.07 + 0.23 + 0.36 + 0.19 + 0.05 + 0.05 + 0.03 + ? = 1

0.98 + ? = 1

? = 0.02

2% probability of choosing a unit with 10 rooms

(c) What is the probability that a unit chosen at random is not a 10-room unit?

0.07 + 0.23 + 0.36 + 0.19 + 0.05 + 0.05 + 0.03 = 0.98

98% probability that a unit chosen at random is not a 10-room unit

(d) What is the probability that a unit chosen at random has less than five rooms?

7% probability it has 3 rooms

23% probability it has 4 rooms. So

7+23 = 30% probability that a unit chosen at random has less than five rooms

(e) What is the probability that a unit chosen at random has three rooms?

7% probability that a randomly chosen owner-occupied housing unit in a certain city has 3 rooms. So

7% probability that a unit chosen at random has less than five rooms

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I need help ASAP!!
Viktor [21]

Answer:


\frac{64}{49}


Step-by-step explanation:


As we can see the given expression as three complex parts and all are being multiplied.


Lets simplify each part separately and then multiply all of them in the end


Part1


(\frac{8.4.2}{8.7})^{2}  

Cancelling 8 in numerator with 8 in denominator


(\frac{4.2}{7})^{2}


(\frac{8}{7})^{2}


\frac{64}{49}


Part2


(\frac{8^{0} }{7^{-3} })^{3}


simpliying


(\frac{1}{7^{-3} })^{3}


({7^{3} })^{3}


7^{9}


Part3


Third part is 7^{-9}, and it does not need to be further simplified


Now multiplying all the three parts


\frac{64}{49}.7^{9}.7^{-9}


\frac{64}{49}.7^{9-9}


\frac{64}{49}.7^{0}


\frac{64}{49}.1


\frac{64}{49}


So our final answer is \frac{64}{49}



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