82 Europe dduuxhxxhhchcch
Answer:
Mass of proton (m) = 1.67×10^(-27) kg
Step-by-step explanation:
Mass of proton (m) = 1.67×10^(-27) kg.
Since, 1 kg = 1000 g
Therefore, m = 1.67x10^(-27+3) g = 1.67x10^(-24) g
Let N no. of protons be present in 1 g. Hence, Nxm = 1 g
So, N = 1 / m = 1 / (1.67x10^(-24))
N = 6x10^(23) (approx.)
Exact mass of proton gives N = 6.022 x 10^(23).
That is a very special no. In fact, it is the Avogadro’s constant used frequently in chemistry. Avogadro’s no. is actually the number of atoms in exactly 12 g of C-12 isotope of carbon. Since, the atomic mass of C-12 is 12 u (unified mass), then again the no. of carbon atoms turn out to be N.
Answer:
B and C work. A and D do not.
Step-by-step explanation:
This is one of those questions that you have to go through each answer to see what the results are. You don't have to go far to eliminate A and D so let's do that first.
A]
5n + 6
Let n = 1
5(1) + 6
5 + 6= 11
However there is trouble beginning with n = 2
5*2 + 6
10 + 6
16 All you need is one wrong answer and the choice is toast. So A won't work.
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Try D
6(n - 1)+ 5
n=0
6*(-1) + 5
-6 + 5
- 1
And D has been eliminated with just 1 attempt. n= 2 or n = 1 would be even worse. D is not one of the answers.
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B
Let n = 1
6(1) + 5
6 + 5
11 The first term works.
n = 2
6*(2) + 5
12 + 5
17 and n = 2 works as well. Just in case it is hard to believe, let's try n = 3 because so far, everything is fine.
n = 3
6*(3) + 5
18 + 5
23 And this also works. I'll let you deal with n = 4
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C
n = 0
6(0 + 1) + 5
6*1 + 5
6 + 5
11
n = 1
6(1 + 1) + 5
6*2 + 5
12 + 5
17 which works.
So C is an answer.