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Blababa [14]
2 years ago
15

Find me X please i will give you 15 points

Mathematics
2 answers:
Fantom [35]2 years ago
6 0

Answer:

x=145

Step-by-step explanation:

A circle have at max 360 degrees.

40 + 85 + 90 + x = 360

125 + 90  + x = 360

215 + x = 360

x = 145

k0ka [10]2 years ago
4 0

Answer:

145

Step-by-step explanation:

there is 360 degrees in a circle . 85 , 40 and the right angle which is 90 add up to 215 so you subtract 215 from 360 to get 145

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Suppose the man in the St. Ives poem has x wives, each wife has x sacks, each sack has x cats, and each cat has x kits. Write an
Harrizon [31]

Answer:

x^{1} wives

x^{2} sacks

x^{3} cats

x^{4} kits

Suppose the man in the St. Ives poem has x wives, each wife has x sacks, each sack has x cats, and each cat has x kits. Write an expression using exponents that represents the total number of kits, cats, sacks, and wives going to St .Ives.

Step-by-step explanation:

x^{1} wives

If each of the "x" wives has "x" sacks, so the number of sacks is:

x^{2} sacks

If each of the "x" wives has "x" sacks, and each sack has "x" cats, so the number of cats is:

x^{3} cats

If each of the "x" wives has "x" sacks, and each sack has "x" cats, and each cat has "x" kits, so the number of kits is:

x^{4} kits

8 0
3 years ago
On a linear X temperature scale, water freezes at −115.0°X and boils at 325.0°X. On a linear Y temperature scale, water freezes
belka [17]

Answer:

The current temperature on the X scale is 1150 °X.

Step-by-step explanation:

Let is determine first the ratio of change in X linear temperature scale to change in Y linear temperature scale:

r = \frac{\Delta T_{X}}{\Delta T_{Y}}

r = \frac{325\,^{\circ}X-(-115\,^{\circ}X)}{-25\,^{\circ}Y - (-65.00\,^{\circ}Y)}

r = 11\,\frac{^{\circ}X}{^{\circ}Y}

The difference between current temperature in Y linear scale with respect to freezing point is:

\Delta T_{Y} = 50\,^{\circ}Y - (-65\,^{\circ}Y)

\Delta T_{Y} = 115\,^{\circ}Y

The change in X linear scale is:

\Delta T_{X} = r\cdot \Delta T_{Y}

\Delta T_{X} = \left(11\,\frac{^{\circ}X}{^{\circ}Y} \right)\cdot (115\,^{\circ}Y)

\Delta T_{X} = 1265\,^{\circ}X

Lastly, the current temperature on the X scale is:

T_{X} = -115\,^{\circ}X + 1265\,^{\circ}X

T_{X} = 1150\,^{\circ}X

The current temperature on the X scale is 1150 °X.

5 0
3 years ago
A solid metal rectangular pyramid has a base that measures 16 cm by 25 cm The Solid is melted and recast into a solid cavare pyr
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5 0
2 years ago
A new club sent out 288 coupons to boost sales for next year's memberships. They provided 5 times as many to potential members t
Aliun [14]

Answer:

D. 48

Step-by-step explanation:

We don't know the numbers of coupons sent to existing members and to potential members, but we know a relationship between the number.

They sent 5 times as many coupons to potential members as they did to existing members.

Let x = number of coupons sent to existing members.

Then 5x = number of coupons sent to potential members.

The total number of coupons sent was x + 5x = 6x

The total number of coupons sent was 288.

Therefore, 6x must equal 288 giving us an equation with a single variable.

6x = 288

x = 48

Answer: 48

7 0
3 years ago
What are the requirements for chemical labels?
Masja [62]

Includes critical information you need to identify the chemical , Includes warnings about the chemical , Legible are the requirements for chemical labels

<u>Step-by-step explanation:</u>

Labels need to produce guidance on how to manage the chemical so that chemical users are notified about how to guard themselves.  That data about chemical hazards be dispatched on labels using quick visual notations (Legible)  to inform the user, granting instant identification of the hazards.

Labels, as described in the HCS, are a relevant group of written, printed or graphic information elements concerning a hazardous chemical that are attached to, printed on, or added to the immediate container of a hazardous chemical, or to the outside packaging.

8 0
3 years ago
Read 2 more answers
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