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STALIN [3.7K]
3 years ago
9

If k = -3 what is the value of k + (2k - 10) ? A. –19 B. –7 C. 1 D. –14

Mathematics
1 answer:
gladu [14]3 years ago
3 0

Answer:

A

Step-by-step explanation:

We have the expression k+(2k-10)

We want to find the value when k is -3. So, substitute -3 for k and evaluate:

\Rightarrow (-3)+(2(-3)-10)

Multiply:

=-3+(-6-10)

Subtract:

=-3+(-16)

Add:

=-19

Therefore, our answer is A.

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SpyIntel [72]

Answer:

The domain of the function is all real values of x, except x = 4 and x = 2

Step-by-step explanation:

We are given the following function:

f(x) = \frac{x+1}{x^2-6x+8}

It's a fraction, so the domain is all the real values except those in which the denominator is 0.

Denominator:

Quadratic equation with a = 1, b = -6, c = 8

Using bhaskara, the denominator is 0 for these following values of x:

\Delta = (-6)^2 - 4(1)(8) = 36-32 = 4

x_{1} = \frac{-(-6) + \sqrt{4}}{2} = 4

x_{2} = \frac{-(-6) - \sqrt{4}}{2} = 2

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8 0
3 years ago
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PSYCHO15rus [73]

Let x = cost of one skirt

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Let's solve this by elimination. Multiply the second equation by -1

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$54.42 = x. Plug this into one of our original equations.

$452.62 = 6(54.42) + 5y. Multiply 6 by 54.42

$452.62 = 326.52 + 5y. Subtract 326.52 from each side.

$126.1 = 5y. Divide each side by 5

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Answer:

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Find:

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