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Fudgin [204]
3 years ago
5

WILL GIVE BRAINLIEST!!!! A boat leaves the dock on shore and rides to a neighboring inlet. After docking for a while, the boat r

ides back to shore. On the journey back, however, the boat is driving into the wind so needs to go a little slower. The graph below represents part of the distance the boat traveled from it's home dock as a function of time.
Choose the correct description for the last portion of the graph based on the given situation.


The graph will decrease at a lesser rate than it increased previously.

The graph will increase again, only at a greater rate than before.

The graph will decrease at a greater rate than it increased previously.

The graph will increase again, only at a lesser rate than before.

Mathematics
1 answer:
melamori03 [73]3 years ago
8 0
Did you get the answer?
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❗❗❗❗HELP❗❗❗❗
just olya [345]

The power increases by 21% per hour. 21% written as a decimal is 0.21.

Because it increases you would multiply the starting value by 1.21 times the number of hours (t).

That needs to be less than or equal to 100,00

The equation would be:

C: 15,040(1.21)t ≤ 100,000

6 0
3 years ago
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A chemist is using 333 milliliters of a solution of acid and water. If 19.6% of the solution is acid, how many milliliters of ac
sesenic [268]

65.27mm of acid is present in solution.

Step-by-step explanation:

Given,

Quantity of solution = 333mm

Acid Percentage = 19.6%

Quantity of acid = 19.6% of Quantity of Solution

Quantity\ of\ acid=\frac{19.6}{100}*333\\Quantity\ of\ acid=\frac{6526.8}{100}\\Quantity\ of\ acid=65.27mm

65.27mm of acid is present in solution.

Keywords: Percentage

Learn more about percentages at:

  • brainly.com/question/10435836
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3 0
3 years ago
Mark took 30 minutes to finish lunch describe the turn the minute hand made
andre [41]
The hand went around 7 numbers.
7 0
3 years ago
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Please help ASAP 40 pts
vekshin1
A. 20

Sims angles C and B are each 80 degrees, angle A must be 20 degrees
8 0
3 years ago
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Find the cosine of both angle A and angle B.
Svetach [21]
We know that

cos A=adjacent side angle A/hypotenuse
adjacent side angle A=24 units
hypotenuse=26 units

cos A=24/26-----> 12/13

cos B=adjacent side angle B/hypotenuse
adjacent side angle B=10 units
hypotenuse=26 units

cos B=10/26------> 5/13

the answers are
cos A=12/13
cos B=5/13

cot A=adjacent side angle A/opposite side angle A
adjacent side angle A=24 units
opposite side angle A=10 units
cot A=24/10------> cot A=12/5

cot B=adjacent side angle B/opposite side angle B
adjacent side angle B=10 units
opposite side angle B=24 units
cot B=10/24------> cot B=5/12


8 0
3 years ago
Read 2 more answers
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