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Zielflug [23.3K]
3 years ago
15

A radiator contains 15 quarts of fluid, 30% of which is antifreeze. How much fluid should be drained and replaced with pure anti

freeze so that the new mixture is 35% antifreeze? (Round your answer to two decimal places.)
Mathematics
1 answer:
Annette [7]3 years ago
5 0
<span>%Antifreeze=<span><span>V<span>Antifreeze</span></span><span>V<span>Fluid</span></span></span></span> <span><span>V<span>Fluid</span></span>=<span><span>V<span>Antifreeze</span></span><span>%Antifreeze</span></span></span> <span><span>V<span>Antifreeze</span></span>=<span>V<span>fluid</span></span>∗%Antifreeze</span> I want to find the amount of antifreeze in a 15 quart solution with 30% antifreeze <span><span>V<span>Antifreeze</span></span>=15∗0.30</span> =18/4 quarts of antifreeze Similarly, I want to find the amount of antifreeze in a 15 quart solution with 35% antifreeze first. <span><span>V<span>Antifreeze</span></span>=15∗0.35</span> = 21/4 quarts of antifreeze


<span>the difference between 21/4 and 18/4 is 3/4 quarts, which is the amount of pure antifreeze I've added in.
</span><span>
SO the V_fluid I replaced with 3/4 quarts of antifreeze is (3/4)/ 0.35</span>


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