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Pepsi [2]
2 years ago
11

David's money is three times Siti's money. Farid has RM 150 less than Siti. The total amount of their money is RM 2 000. How muc

h do each of them have? ​
Mathematics
1 answer:
mart [117]2 years ago
3 0

Answer:

Siti's money = RM 430

David = RM 1,290

Farid = RM 280

Step-by-step explanation:

Let

Siti's money = x

David = 3x

Farid = x - 150

Total of their money = RM 2 000

x + 3x + (x - 150) = 2000

4x + x - 150 = 2000

5x = 2000 + 150

5x = 2,150

x = 2,150/5

x = RM 430

Siti's money = x

= RM 430

David = 3x

= 3(430)

= RM 1,290

Farid = x - 150

= 430 - 150

= RM 280

You might be interested in
The sequence$$1,2,1,2,2,1,2,2,2,1,2,2,2,2,1,2,2,2,2,2,1,2,\dots$$consists of $1$'s separated by blocks of $2$'s with $n$ $2$'s i
kicyunya [14]

Consider the lengths of consecutive 1-2 blocks.

block 1 - 1, 2 - length 2

block 2 - 1, 2, 2 - length 3

block 3 - 1, 2, 2, 2 - length 4

block 4 - 1, 2, 2, 2, 2 - length 5

and so on.


Recall the formula for the sum of consecutive positive integers,

\displaystyle \sum_{i=1}^j i = 1 + 2 + 3 + \cdots + j = \frac{j(j+1)}2 \implies \sum_{i=2}^j = \frac{j(j+1) - 2}2

Now,

1234 = \dfrac{j(j+1)-2}2 \implies 2470 = j(j+1) \implies j\approx49.2016

which means that the 1234th term in the sequence occurs somewhere about 1/5 of the way through the 49th 1-2 block.

In the first 48 blocks, the sequence contains 48 copies of 1 and 1 + 2 + 3 + ... + 47 copies of 2, hence they make up a total of

\displaystyle \sum_{i=1}^48 1 + \sum_{i=1}^{48} i = 48+\frac{48(48+1)}2 = 1224

numbers, and their sum is

\displaystyle \sum_{i=1}^{48} 1 + \sum_{i=1}^{48} 2i = 48 + 48(48+1) = 48\times50 = 2400

This leaves us with the contribution of the first 10 terms in the 49th block, which consist of one 1 and nine 2s with a sum of 1+9\times2=19.

So, the sum of the first 1234 terms in the sequence is 2419.

8 0
1 year ago
I drove 380 miles using 14 gallons of gas. At this rate, how many gallons of gas would I need to drive 418 miles?
ser-zykov [4K]

Answer:

15.4 gallons .

Step-by-step explanation:

The rate of gas used  = 380/14 = 27.14 gallons per gallon.

So for each gallon used  you drive 27.14 miles.

So number of gallons used when travelling 418 miles = 418/27.14

= 15.4 gallons .


8 0
3 years ago
Read 2 more answers
B) 2x² - 4x + 3 = 0<br> a) x² + 3x – 10 = 0
kozerog [31]

Answer:

a. x = 2 , x = -5

b. no real roots

Step-by-step explanation:

<u>a. x² + 3x – 10</u>

= x² - 2x + 5x - 10

= x (x²/x - 2x/x) + 5 (5x/5 - 2*5/5)

= (x - 2) (x + 5)

x - 2 = 0                            x + 5 = 0

 + 2    +2                             -5     -5

--------------                         ---------------

x = 2                                   x = -5

x = 2 , x = -5

<u>b. 2x² - 4x + 3 </u>

This can't be solved because the equation has no real roots, and also the discriminant is negative.

3 0
2 years ago
Please help me out!!
solniwko [45]
The slope is 1 because it is parallel and y=x+b, so, 2=-3+b and b=5
y=x+5

8 0
3 years ago
The heights of men in a certain population follow a normal distribution with mean 69.7 inches and standard deviation 2.8 inches.
Mama L [17]

Answer:

a) P(Y > 76) = 0.0122

b) i) P(both of them will be more than 76 inches tall) = 0.00015

   ii) P(Y > 76) = 0.0007

Step-by-step explanation:

Given - The heights of men in a certain population follow a normal distribution with mean 69.7 inches and standard deviation 2.8 inches.

To find - (a) If a man is chosen at random from the population, find

                    the probability that he will be more than 76 inches tall.

              (b) If two men are chosen at random from the population, find

                    the probability that

                    (i) both of them will be more than 76 inches tall;

                    (ii) their mean height will be more than 76 inches.

Proof -

a)

P(Y > 76) = P(Y - mean > 76 - mean)

                 = P( \frac{( Y- mean)}{S.D}) > \frac{( 76- mean)}{S.D})

                 = P(Z >  \frac{( 76- mean)}{S.D})

                 = P(Z > \frac{76 - 69.7}{2.8})

                 = P(Z > 2.25)

                 = 1 - P(Z  ≤ 2.25)

                 = 0.0122

⇒P(Y > 76) = 0.0122

b)

(i)

P(both of them will be more than 76 inches tall) = (0.0122)²

                                                                           = 0.00015

⇒P(both of them will be more than 76 inches tall) = 0.00015

(ii)

Given that,

Mean = 69.7,

\frac{S.D}{\sqrt{N} } = 1.979899,

Now,

P(Y > 76) = P(Y - mean > 76 - mean)

                 = P( \frac{( Y- mean)}{\frac{S.D}{\sqrt{N} } })) > \frac{( 76- mean)}{\frac{S.D}{\sqrt{N} } })

                 = P(Z > \frac{( 76- mean)}{\frac{S.D}{\sqrt{N} } })

                 = P(Z > \frac{( 76- 69.7)}{1.979899 }))

                 = P(Z > 3.182)

                 = 1 - P(Z ≤ 3.182)

                 = 0.0007

⇒P(Y > 76) = 0.0007

6 0
2 years ago
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