First, we must determine the slope of the line. The slope can be found by using the formula:
m
=
y
2
−
y
1
x
2
−
x
1
Where
m
is the slope and (
x
1
,
y
1
) and (
x
2
,
y
2
) are the two points on the line.
Substituting the values from the points in the problem gives:
m
=
−
3
−
5
−
3
−
5
=
−
8
−
8
=
1
Next, we can use the point-slope formula to get an equation for the line. The point-slope formula states:
(
y
−
y
1
)
=
m
(
x
−
x
1
)
Where
m
is the slope and
(
x
1
y
1
)
is a point the line passes through.
Substituting the slope we calculated and the first point from the problem gives:
(
y
−
5
)
=
1
(
x
−
5
)
The standard form of a linear equation is:
A
x
+
B
y
=
C
Where, if at all possible,
A
,
B
, and
C
are integers, and A is non-negative, and, A, B, and C have no common factors other than 1
We can now transform the equation we wrote to standard form as follows:
y
−
5
=
x
−
5
−
x
+
y
−
5
+
5
=
−
x
+
x
−
5
+
5
−
x
+
y
−
0
=
0
−
0
−
x
+
y
=
0
−
1
(
−
x
+
y
)
=
−
1
⋅
0
x
−
y
=
0
1
x
+
−
1
y
=
0
Answer:
To determine the number of shirts that Lisa can buy, knowing that each one is worth $ 14, that she can spend a maximum of $ 150 and that she will also buy a pair of jeans for $ 58 and a pair of shoes for $ 39, the following calculation must be performed:
(150 - 58 - 39) / 14 = X
53/14 = X
3.78 = X
53 - (14 x 3) = X
11 = X
Therefore, Lisa can buy 3 T-shirts, and she will have 11 dollars left over.
Answer:
D) 3.8 cm
Step-by-step explanation:
There are several ways this problem can be solved. Maybe the easiest is to use the Law of Cosines to find angle BAC. Then trig functions can be used to find the length of the chord.
__
In triangle BAC, the Law of Cosines tells us ...
a² = b² +c² -2bc·cos(A)
A = arccos((b² +c² -a²)/(2bc)) = arccos((8² +6² -3²)/(2·8·6)) = arccos(91/96)
A ≈ 18.573°
The measure of half the chord is AB times the sine of this angle:
BD = 2(AB·sin(A)) ≈ 3.82222
The length of the common chord is about 3.8 cm.
_____
<em>Additional comment</em>
Another solution can be found using Heron's formula to find the area of triangle ABC. From that, its altitude can be found.
Area ABC = √(s(s-a)(s-b)(s-c)) . . . . where s=(a+b+c)/2
s=(3+8+6)/2 = 8.5
A = √(8.5(8.5 -3)(8.5 -8)(8.5 -6)) = √54.4375 ≈ 7.64444
The altitude of triangle ABC to segment AC is given by ...
A = 1/2bh
h = 2A/b = 2(7.64444)/8 = 1.911111
BD = 2h = 3.822222
Answer:
c,d,g,h
Step-by-step explanation: