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Lelu [443]
4 years ago
13

When Calcium (Ca) is mixed with Hydrochloric acid (HCI), a single-displacement reaction occurs. What will be the product or prod

ucts?
a) CaCI2
b) CaCI2+H2
c) Ca+HCI
d) CI and H

Chemistry
2 answers:
zhannawk [14.2K]4 years ago
7 0

<u>Answer:</u> The correct answer is Option b.

<u>Explanation:</u>

Single displacement reaction is defined as the reaction in which more reactive element displaces a less reactive element from its chemical reaction.

The reactivity of metal is determined by a series known as reactivity series. The metals lying above in the series are more reactive than the metals which lie below in the series.

When calcium metal reacts with hydrochloric acid, it leads to the formation of a salt known as calcium chloride and also releases hydrogen gas.

The chemical equation for the above reaction follows:

Ca(s)+2HCl(aq.)\rightarrow CaCl_2(s)+H_2(g)

Hence, the correct answer is Option b.

matrenka [14]4 years ago
4 0
The correct answer is b. In a single-displacement reaction one element replaces another one, and because of BrINClHOF we know that hydrogen must have a 2 with it when it's by itself. Since calcium is +2 and chlorine is -1, you have to cross the charges. So it would be CaCl2.

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What is the freezing point of a solution that contains 36.0 g of glucose ( ) in 500.0 g of water? ( for water is 1.86°c/m. the m
Marizza181 [45]
Answer: - 1.86°C

Explanation:

The depression of freezing points of solutions is a colligative property.

That means that the depression of freezing points of solutions depends on the number of molecules or particles dissolved and not the nature of the solute.

To solve the problem follow these steps:

Data:

Tf = ?
solute = glucosa (this implies i factor is 1)
mass of solue = 36.0 g
mass of water = 500 g
Kf = 1.86 °/m
mm glucose = 180.0 g / mol

2) Formulas

Tf = Normal Tf - ΔTf

ΔTf = i * kf * m

m = number of moles of solute / kg of solvent

number of moles of solute = mass in grams / molar mass

3) Solution

number of moles of solute = 36.0 g / 180.0 g/mol = 0.2 mol

m = 0.2 mol / 0.5 kg = 1.0 m

ΔTf = i * Kb * m = 1 * 1.86 °C/m * 1 m = 1.86°C

Tf = 0°C - 1.86°C = - 1.86°C

Answer: - 1.86 °C
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3 years ago
Write the balanced equation showing the decomposition of carbonic acid and sulfurous acid.
Travka [436]

Explanation:

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qaws [65]

Answer:

0.897 J/g.⁰C

Explanation:

Given the following data:

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The amount of heat (q) is calculated as follows:

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Thus, we introduce the data in the mathematical expression to calculate the specific heat (Cp):

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Answer:

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It cannot be D, as most metals are malleable.

This leaves B, which is not true about metals, as a lot are very good conductors.

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