Answer:
Graph A
Step-by-step explanation:
I already did this
Demand
D(q)=(12-q)^(1/2)
Revenue,
R(q)=q*D(q)=q*sqrt(12-q)
At maximum revenue,
R'(q)=0
where
R'(q)=sqrt(12-q)-q/[2(sqrt(12-q))]=0
Solve for q=8.
Hence, quantity=8, price=sqrt(12-q)=sqrt(12-8)=sqrt(4)=2
The answer is 2/6 because both of the numbers can be divided by 2. 4/2 is 2 and 12/2 is 6
-5^9 ; (5^3)^-2 <---- Neither of these is equal to 1/(5^9)
3^5 * 3^2; 3^20/3^2 <--- Neither of these is equal to 3^10
4*x; x^-4/x^8 <---- Neither of these is (always) equal to x^4
0 <--- This is the only value not equal to 1, the value of 8^0
-10.6, and 9/10, are the constants