Find an equation for the perpendicular bisector of the line segment whose endpoints are
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Answer:
Therefore, equation of the line that passes through (16,-7) and is perpendicular to the line is
Step-by-step explanation:
Given:
To Find:
Equation of line passing through ( 16, -7) and is perpendicular to the line
Solution:
...........Given
Comparing with,
Where m =slope
We get
We know that for Perpendicular lines have product slopes = -1.
Substituting m1 we get m2 as
Therefore the slope of the required line passing through (16 , -7) will have the slope,
Now the equation of line in slope point form given by
Substituting the point (16 , -7) and slope m2 we will get the required equation of the line,
Therefore, equation of the line that passes through (16,-7) and is perpendicular to the line is