Answer:
The correct option is C.
Step-by-step explanation:
The least common multiple (LCM) of any two numbers is the smallest number that they both divide evenly into.
The given terms are
and
.
The factored form of each term is


To find the LCM of given numbers, multiply all factors of both terms and common factors of both terms are multiplied once.


The LCM of given terms is
. Therefore the correct option is C.
Your answer would be 100.
Answer:
See explanation, and ask for more details if unclear!
Step-by-step explanation:
The perfect square of this equation is
, since the square would be
. 1/4=4/16, meaning that you can set up the equation in the following way:


Take the square root of both sides:

Add 1/2 to both sides:
. Hope this helps!