Is it 2 different questions or just one?
Y = x^2 - 64
x^2 - 64 = 0
x^2 = 64
x^2 = 8^2
x = 8 and x = -8
answer is B. x = 8 and x = -8
Given:
A line passes through (1,-2) and is perpendicular to 
.
To find:
The equation of that line.
Solution:
We have, equation of perpendicular line.
Slope of this line is
Product of slope of two perpendicular lines is -1.
Now, slope of required line is 
and it passes through (1,-2). So, the equation of line is
where, m is slope.
Therefore, the equation of required line is .
-2/5=-.4
-7=-7
These two are repeating decimals.
3/9=.3333334
11/12=.9166667
Answer:
b1 = 2 ; r = 3
Step-by-step explanation:
Given that :
if b3 −b1 = 16 and b5 −b3 = 144.
For a geometric series :
Ist term = a
Second term = ar
3rd term = ar^2
4th term = ar^3
5th term = ar^4 ;...
If b3 - b1 = 16;
ar^2 - a = 16
a(r^2 - 1) = 16 - - - (1)
b5 - b3 = 144
ar^4 - ar^2 = 144
ar^2(r^2 - 1) = 144 - - - - (2)
Divide (1) by (2)
a(r^2 - 1) / ar^2(r^2 - 1) = 16 /144
a / ar^2 = 1 / 9
ar^2 = 9a
Substitute for a in ar^2 - a = 16
9a - a = 16
8a = 16
a = 2
From ar^2 - a = 16
2r^2 - 2 = 16
2r^2 = 16 + 2
2r^2 = 18
r^2 = 18 / 2
r^2 = 9
r = √9
r = 3
Hence ;
a = b1 = 2 ; r = 3
