When multiplying 2 fractions is the product greater than the factors?

1 answer:

3 0

No I do not believe so... When multiplying 2 fractions the product is not greater than the factors.

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seropon [69]

Answer:

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5 0

3 years ago

Please help! Can anyone help me out with this question?

TEA [102]

Answer:

$\displaystyle h'(s) = 64s + 20$

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Distributive Property

Algebra I

Terms/Coefficients

Calculus

Derivatives

Derivative Notation

Derivative of a constant is 0

Basic Power Rule:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Derivative Rule [Product Rule]: $\displaystyle \frac{d}{dx} [f(x)g(x)]=f'(x)g(x) + g'(x)f(x)$

Step-by-step explanation:

Step 1: Define

$\displaystyle h(s) = (-8s - 9)(-4s + 2)$

Step 2: Differentiate

[Derivative] Product Rule: $\displaystyle h'(s) = \frac{d}{ds}[(-8s - 9)](-4s + 2) + (-8s - 9)\frac{d}{ds}[(-4s + 2)]$
[Derivative] Basic Power Rule: $\displaystyle h'(s) = (1 \cdot -8s^{1 - 1} - 0)(-4s + 2) + (-8s - 9)(1 \cdot -4s^{1 - 1} - 0)$
[Derivative] Simplify: $\displaystyle h'(s) = (-8)(-4s + 2) + (-8s - 9)(-4)$
[Derivative] Distribute [Distributive Property]: $\displaystyle h'(s) = 32s - 16 + 32s + 36$
[Derivative] Combine like terms: $\displaystyle h'(s) = 64s + 20$