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3 years ago

As the average kinetic energy of a substance increases, the tempature of the sample

Physics

2 answers:

taurus [48]3 years ago

6 0

I have no clue. Sorry bro

BigorU [14]3 years ago

6 0

B- would also increase because of the work being put into it.

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The maximum height a typical person can jump is about 60cm (0.6m). By how much does the gravitational potential energy increase

sasho [114]

The gravitational potential energy will increase by 423.36 J

<h3>How to determine the potential energy at ground level</h3>

Mass (m) = 72 kg
Acceleration due to gravity (g) = 9.8 m/s²
Height (h) = 0 m
Potential energy at ground level (PE₁) =?

PE = mgh

PE₁ = 72 × 9.8 × 0

PE₁ = 0 J

<h3>How to determine the potential energy at 60 cm (0.6 m)</h3>

Mass (m) = 72 kg
Acceleration due to gravity (g) = 9.8 m/s²
Height (h) = 0.6 m
Potential energy at 60 cm (0.6 m) (PE₂) =?

PE = mgh

PE₂ = 72 × 9.8 × 0.6

PE₂= 423.36 J

<h3>How to determine the change in potential energy </h3>

Potential energy at ground level (PE₁) = 0 J
Potential energy at 60 cm (0.6 m) (PE₂) = 423.36 J
Change in potential energy =?

Change in potential energy = PE₂ - PE₁

Change in potential energy = 423.36 - 0

Change in potential energy = 423.36 J

Learn more about energy:

brainly.com/question/10703928

#SPJ1

8 0

2 years ago

If a charge at 60c flow in a conductor for 30 second then the current that flow in a conductor is

saw5 [17]

Explanation:

<h3>Given</h3>

- Charge = 60c

time = 30 sec

current

<h3>Solution </h3>

Current = Charge/time

I = V/T

I = 60/30

I = 2 ampere

More to know -

I = Current

V = Charge

T = Time

3 0

3 years ago

You stand on a bridge above a river and drop a rock into the water below from a height of 25 m. (Assume no air resistance)

Ilia_Sergeevich [38]

PART a)

here when stone is dropped there is only gravitational force on it

so its acceleration is only due to gravity

so we will have

$a = g = 9.8 m/s^2$

Part b)

Now from kinematics equation we will have

$y = v_i t + \frac{1}{2} at^2$

now we have

y = 25 m

so from above equation

$25 = 0 + \frac{1}{2}(9.8 )t^2$

$t = 2.26 s$

Part c)

If we throw the rock horizontally by speed 20 m/s

then in this case there is no change in the vertical velocity

so it will take same time to reach the water surface as it took initially

So t = 2.26 s

Part D)

Initial speed = 20 m/s

angle of projection = 65 degree

now we have

$v_x = vcos\theta$

$v_x = 20 cos65 = 8.45 m/s$

$v_y = vsin\theta$

$v_y = 20 sin65 = 18.13 m/s$

PART E)

when stone will reach to maximum height then we know that its final speed in y direction becomes zero

so here we can use kinematics in Y direction

$v_f - v_y = at$

$0 - 18.13 = (-9.8) t$

$t = 1.85 s$

so it will take 1.85 s to reach the top

5 0

3 years ago

Which one of the following substances is a liquid fuel used in rocket engines?

viva [34]

The substance which is a liquid fuel used in rocket engines is liquid oxygen. The correct answer is A.

5 0

3 years ago

What does a fire burn a hole right in the middle of the chair???

earnstyle [38]

i dont understand wat ur tryna say ma dude but whatever it is its.............PIZZA

4 0

3 years ago