PLZ HELP ME Is there ever a situation where an ant will have more momentum than an elephant? Explain why or why not? Question 2
2 answers:
An ant will have higher momentum than elephant only if elephant is standing still.
Explanation:
The word momentum is defined as product of object’s mass and velocity
buy which it moves and the momentum can be denoted by vector quantity
.
Whose product of mass and the velocity is more; its momentum will be more.
If elephant stands still, means its velocity is equal to zero, then the product of its mass and velocity will be zero. Hence, it will have 0 momentum.
Since, the mass of ant is insignificantly small but have velocity for moving. So, the ant have small momentum but somewhat greater than zero.
Therefore, the ant will have higher momentum than elephant only if elephant stands still.
If an ant will stand still it have zero velocity, so the momentum will be equal to zero. Hence, this option is also incorrect.
The option “The elephant has much high mass” is incorrect because having high mass but zero velocity will result in no momentum.
Thus, an ant will have higher momentum than elephant only if elephant is standing still.
Learn More:
1. Momentum <u>brainly.com/question/11942991 </u>
2. More about momentum <u>brainly.com/question/2872275 </u>
3. Force and motion <u>brainly.com/question/11947870 </u>
Answer Details:
Grade: High School
Subject: Physics
Chapter: Momentum
Keywords:
Ant, elephant, momentum, more, explain, standing, mass, fast, still, change, object, velocity, force, times, impulse, acting, negligible, product, zero.
You might be interested in
Answer:
T = 295.57 s
Explanation:
given,
mass of the rocket = 200 Kg
mass of the fuel = 100 Kg
acceleration = 35 m/s²
time, t = 35 s
time taken by the rocket to hit the ground, = ?
Final speed of the rocket when fuel is empty
using equation of motion
v = u + a t
v = 0 + 35 x 35
v = 1225 m/s
height of the rocket where fuel is empty
v² = u² + 2 a s
1225² = 0 + 2 x 35 x h₁
h₁ = 21437.5 m
After 35 s the rocket will be moving upward till the final velocity becomes zero.
Now, using equation of motion to find the height after 35 s
v² = u² + 2 g h₂
0² = 1225² + 2 x (-9.8) h₂
h₂ = 76562.5 m
total height = h₁ + h₂
= 76562.5 m + 21437.5 m = 98000 m
now, time taken by before the rocket hit the ground
using equation of motion
negative sign is used because the distance travel by the rocket is downward.
4.9 t² - 1225 t - 13500 = 0
t = 260.57 s
neglecting the negative sign
total time the rocket was in air
T = t₁ + t₂
T = 35 + 260.57
T = 295.57 s
Time for which rocket was in air is equal to 295.57 s.