The Sun's magnetic field goes through a cycle, called the solar cycle. Every 11 years or so, the Sun's magnetic field completely flips. This means that the Sun's north and south poles switch places. Then it takes about another 11 years for the Sun's north and south poles to flip back again.
Integrating the velocity equation, we will see that the position equation is:

<h3>How to get the position equation of the particle?</h3>
Let the velocity of the particle is:

To get the position equation we just need to integrate the above equation:


Then:


Replacing that in our integral we get:


Where C is a constant of integration.
Now we remember that 
Then we have:

To find the value of C, we use the fact that f(0) = 0.

C = -1 / 3
Then the position function is:

Integrating the velocity equation, we will see that the position equation is:

To learn more about motion equations, refer to:
brainly.com/question/19365526
#SPJ4
Let's break the question into two parts:
1) The force needed in Ramp scenario.
2) The effort force needed in the lever scenario.
1. Ramp Scenario: In an incline, the only component of cart's weight(
mg) that is in the direction of motion is
. Therefore the effort force in this case must be equal or greater than
.
Now we need to find

.

is the angle between the incline of the ramp and the ground.
Since the height is
5m and the length of the ramp is
8m, 
would be
5/8 or 0.625. Now that you have

, mutiple it with
mg.
=> m*g*

= 20 * 10 * 5 / 8. (Taking g = 10 m/s² for simplicity) = 125N
Therefore, the minimum Effort force you would require in this case is
125N.
2. Lever Scenario:
Just apply "moment action" in this case, which is:


= ?

= mg = 20 * 10 = 200N

= 10m

= 1m
Plug-in the values in the above equation:

= 200/10=
20NAs 20N << 125N, the best choice is to use lever.
"Wheel & Axle" <span>can be described as a shaft that is attached to the center of a wheel
Hope this helps!</span>