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bearhunter [10]

3 years ago

12

a square loop of wire side 3.0 cm carries 3.0 A of current. A uniform magnetic field of magnitude 0.67 T makes an angle of 37 de

grees with the plane of the loop. What is the magnitude of the torque on the loop

1 answer:

Varvara68 [4.7K]3 years ago

8 0

Explanation:

Below is an attachment containing the solution.

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. A magnetic field has a magnitude of 0.078 T and is uniform over a circular surface whose radius is 0.10 m. The field is orient

Dmitriy789 [7]

Answer:

The magnetic flux through surface is $2.22 \times 10^{-3}$ Wb

Explanation:

Given :

Magnitude of magnetic field $B = 0.078$ T

Radius of circle $r = 0.10$ m

Angle between field and surface normal $\theta =$ 25°

From the formula of flux,

$\phi = B.A$

$\phi = BA\cos \theta$

Where $\theta =$ angle between magnetic field line and surface normal, $A =$ area of circular surface.

$A = \pi r^{2}$

$A = 3.14 \times (0.10) ^{2}$

$A = 0.0314$ $m^{2}$

Magnetic flux is given by,

$\phi = 0.078 \times 0.0314 \times \cos 25$

$\phi = 2.22 \times 10^{-3}$ Wb

Therefore, the magnetic flux through surface is $2.22 \times 10^{-3}$ Wb

6 0

4 years ago

Measuring the diameter of a specific object might include which pair of SI units

VLD [36.1K]

Well, the diameter of a circle is simply a length, so your measurement will have units of length. We just have to find an answer that has only units of length.

A). gram, second . . . mass and time. That can't be it.

B). kilogram, ampere . . . mass and current. That can't be it.

C). centimeter, meter . . . both lengths. This one is looking good.

D). candela, mole . . . light intensity and some chemical thing. That can't be it.

So it can't be anything else on this list but <em>C</em> .

8 0

3 years ago

Two boys are at the top of a waterslide at Seven Peaks Water Park. One boy (boy A) slips off the top of the tower and falls unob

Illusion [34]

Answer: boy B, same

Explanation:

Given

One boy trips off the waterslide while the other starts sliding down

As there is no horizontal velocity, both boys have to travel the same vertical distance.

Their starting vertical velocity is zero and they need to travel the same vertical distance. Therefore, both boys splash water with the same velocity.

The time taken by boy B is more than boy A as boy B will travel some horizontal distance due to slide which will increase its time to reach the bottom.

4 0

3 years ago

How many electrons in Cu

boyakko [2]

Answer:29 electrons

Explanation: If you look on a periodic table, the atomic number is the amount of electrons it has.

3 0

3 years ago

You charge an initially uncharged 65.7-mf capacitor through a 39.1-Ï resistor by means of a 9.00-v battery having negligible int

uysha [10]

In a RC-circuit, with the capacitor initially uncharged, when we connect the battery to the circuit the charge on the capacitor starts to increase following the law:
$Q(t) = Q_0 (1-e^{-t/\tau})$
where t is the time, $Q_0 = CV$ is the maximum charge on the capacitor at voltage V, and $\tau = RC$ is the time constant of the circuit.
Using this law, we can answer all the three questions of the problem.

1) Using $R=39.1 \Omega$ and $C= 65.7 mF=65.7\cdot 10^{-3}F$ , the time constant of the circuit is:
$\tau = RC=(39.1 \Omega)(65.7 \cdot 10^{-3}F)=2.57 s$

2) To find the charge on the capacitor at time $t=1.95 \tau$ , we must find before the maximum charge on the capacitor, which is
$Q_0 = CV=(65.7 \cdot 10^{-3}F)(9 V)=0.59 C$
And then, the charge at time $t=1.95 \tau$ is equal to
$Q(1.95 \tau) = Q_0 (1-e^{-t/\tau})=(0.59 C)(1-e^{-1.95})=0.51 C$

3) After a long time (let's say much larger than the time constant of the circuit), the capacitor will be fully charged, this means its charge will be $Q_0 = 0.59 C$ . We can see this also from the previous formule, by using $t=\infty$ :
$Q(t) = Q_0 (1-e^{-\infty})=Q_0(1-0) = 0.59 C$

4 0

3 years ago