Answer:
LED run before the batteries are depleted is 3.87 hours
Explanation:
given data
battery = 4 AA
battery is rated = 1.2V, 2550 mAh
power = 3 W
efficient = 95%
to find out
How long will the LED run before the batteries are depleted
solution
we consider here power delivered by battery is = x
so power = x × efficient
3 = x 95%
x = 3.15 W
and
voltage by 4 battery is = 4 × 1.2 = 4.8 V
so current will be = 
current = 
current = 0.6577 A
so total discharge hours = 
total discharge hours = 
time = 3.87 hours
so LED run before the batteries are depleted is 3.87 hours
Answer:
V= 14.2m/s
Explanation:
We know that acceleration= dv/dt
So 16m/s²=dv/ dt = v dv/ds
So this wil be
Integral of 16m/s² ds [at 2,2]= integral of v dv at[ 0, v]
So 16[s (3/2)/3/2] at ( s,3) = v²/2
At s= 6m
So v² = 64/3( 6^1.5-3^1.5)
= 14.2m/s
C. Oxygen has a different attraction for electrons in H2O than in CO2
the covalent bond between Hydrogen-Oxygen and Carbon-Oxygen is different because the difference of electronegativity (the tendency of an atom to attract a shared pair of electrons towards itself) between Hydrogen and Oxygen is a lot higher than the difference of electronegativity between Carbon and Oxygen. This difference in electronegativity results in separation of partial electric charge creating polar bonds and giving the molecule a polarity.
Yes it is because the teacher told me in science lol ☺☺
Answer:
I am pretty sure it is A!
:D
