3 years ago

Quick I'll Mark it Brainliest Which of the following statements is true?

Physics

1 answer:

zzz [600]3 years ago

8 0

Answer:

A, B and C

Explanation:

The A, B and C look most probable. Heat energy flared to atmosphere might not be recovered. It could end up heating up the atmosphere.

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.<br>1. How does the arrangement of a pulley system affect its ideal mechanical advantage

lukranit [14]

Answer: In a pulley, the ideal mechanical advantage is equal to the number of rope segments pulling up on the object. The more rope segments that are supporting to do the lifting work, the less pressure that is needed for the job.

Explanation:

7 0

3 years ago

Using a simple machine, a student is able to lift a 500N weight by applying only 100N. What is the mechanical advantage of the s

Vanyuwa [196]

Answer:

The answer is 5

Explanation:

4 0

4 years ago

An object experiences an acceleration of -6.8m/s^2. As a result, it accelerates from 54m/s to a complete stop. how much distance

Kipish [7]

Answer:

210 m

Explanation:

Given:

a = -6.8 m/s²

v₀ = 54 m/s

v = 0 m/s

Find: Δx

v² = v₀² + 2aΔx

(0 m/s)² = (54 m/s)² + 2 (-6.8 m/s²) Δx

Δx ≈ 210 m

6 0

3 years ago

Two charged particles held close together are released. As they move, the force on each particle increases. Therefore, the parti

AnnyKZ [126]

The answer would be B

4 0

3 years ago

Ice skaters often end their performances with spin turns, where they spin very fast about their center of mass with their arms f

vampirchik [111]

Answer:

$\large \boxed{\text{30 rev/s}}$

Explanation:

This question is based on the Law of Conservation of Angular Momentum.

Angular momentum (L) equals the moment of inertia (I) times the angular speed (ω).

L = Iω

If momentum is conserved,

I₁ω₁ = I₂ω₂

Data:

I₁ = 3.5 kg·m²s⁻¹

ω₁ = 6.0 rev·s⁻¹

I₂ = 0.70 kg·m²s⁻¹

Calculation:

$\begin{array}{rcl}I_{1}\omega_{1} &= &I_{2}\omega_{2}\\\text{3.5 kg$\cdot$m$^{2}$}\times \text{6.0 rev/s} &= &\text{0.70 kg$\cdot$m$^{2}$}\times\omega_{2}\\\text{21 rev/s} &= &0.70\omega_{2}\\\omega_{2} & = & \dfrac{\text{21 rev/s}}{0.70}\\\\&=&\textbf{30 rev/s}\\\end{array}\\\text{The skater's final rotational speed is $\large \boxed{\textbf{30 rev/s}}$}$

8 0

4 years ago