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2 years ago

In the diagram ce =12 and be=5 based on the given info ae =

Mathematics

2 answers:

slega [8]2 years ago

7 0

12 - it is congruent to CE

DanielleElmas [232]2 years ago

5 0

The answer is ae=12 that what i got right on my test

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I need to know what the equation is for this graph..

Lostsunrise [7]

Answer:

The choice second

$y = \frac{1}{3} \times ( \frac{1}{4} ) ^{x}$

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1 year ago

-5(-3)(-3) what the product

sukhopar [10]

Answer:

Step-by-step explanation:

(-5) * (-3) * (-3) = -5 * -3 * -3 = 15 * -3 = -45

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2 years ago

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Which of the following fractions is smaller than<br> 1/2

Harman [31]

the answer is C: 3/7

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2 years ago

How do you find the solution of this proportion?<br> 4/9 = m2-1/54 <br> m2 is m to the power of 2

andrew11 [14]

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2 years ago

Past records indicate that the probability of online retail orders that turn out to be fraudulent is 0.08. Suppose that, on a gi

Sunny_sXe [5.5K]

Answer:

The probability that there are 2 or more fraudulent online retail orders in the sample is 0.483.

Step-by-step explanation:

We can model this with a binomial random variable, with sample size n=20 and probability of success p=0.08.

The probability of k online retail orders that turn out to be fraudulent in the sample is:

$P(x=k)=\dbinom{n}{k}p^k(1-p)^{n-k}=\dbinom{20}{k}\cdot0.08^k\cdot0.92^{20-k}$

We have to calculate the probability that 2 or more online retail orders that turn out to be fraudulent. This can be calculated as:

$P(x\geq2)=1-[P(x=0)+P(x=1)]\\\\\\P(x=0)=\dbinom{20}{0}\cdot0.08^{0}\cdot0.92^{20}=1\cdot1\cdot0.189=0.189\\\\\\P(x=1)=\dbinom{20}{1}\cdot0.08^{1}\cdot0.92^{19}=20\cdot0.08\cdot0.205=0.328\\\\\\\\P(x\geq2)=1-[0.189+0.328]\\\\P(x\geq2)=1-0.517=0.483$

The probability that there are 2 or more fraudulent online retail orders in the sample is 0.483.

5 0

2 years ago