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Fiesta28 [93]
3 years ago
6

Solve each linear-quadratic system algebraically. Show all work.

Mathematics
1 answer:
a_sh-v [17]3 years ago
5 0

Answer:

(5, - 8 ) and (- 1, 4 )

Step-by-step explanation:

Given the 2 equations

y = - x² + 2x + 7 → (1)

y = - 2x + 2 → (2)

Substitute y = - 2x + 2 into (1)

- 2x + 2 = - x² + 2x + 7 ← subtract - x² + 2x + 7 from both sides

x² - 4x - 5 = 0 ← in standard form

(x - 5)(x + 1) = 0 ← in factored form

Equate each factor to zero and solve for x

x - 5 = 0 ⇒ x = 5

x + 1 = 0 ⇒ x = - 1

Substitute these values into (2) for corresponding values of y

x = 5 → y = - 2(5) + 2 = - 10 + 2 = - 8 ⇒ (5, - 8)

x = - 1 → y = - 2(- 1) + 2 = 2 + 2 = 4 ⇒ (- 1, 4)

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Answer:

85°

Step-by-step explanation:

Please follow along with these directions on the attached picture so that this makes sense.  I have labeled the picture with the variables I used and the angles I figured out.

Let's start in the top left corner. Remember: triangles always have 180°, and straight lines always have 180°.

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3 years ago
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alexandr402 [8]
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3 years ago
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Hunter-Best [27]
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3 0
3 years ago
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Ede4ka [16]

Answer:

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Step-by-step explanation:

Won't go in-depth since time seems to be of the essence

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2 years ago
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Naily [24]

Answer:  The answer would be A.  Or if that is what you are asking.

Step-by-step explanation:

When you multiply decimals, you multiply like how you would for any other set of numbers. (It doesn't matter if you line the decimal points up or not.)

The only difference between multiplying normal numbers and decimals is the decimal point. How many digits there are to the right of the decimal point is how many times you move the decimal point for the new number to the left.

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