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Rashid [163]
3 years ago
10

A conjecture and the paragraph proof used to prove the conjecture are shown.

Mathematics
2 answers:
kumpel [21]3 years ago
7 0

∠1 and ​ ∠2 ​ form a linear pair, so ∠1 and ∠2 are supplementary by the <u>LINEAR PAIR POSTULATE</u> . Therefore, m∠1 + <u>m∠2</u> = 180° by the definition of supplementary. It is given that ∠2 ≅ <u>∠3</u> so m∠2 = m∠3 by the <u>ANGLE CONGRUENCE POSTULATE</u> . By substitution, m∠1 + m∠3 = 180°, so ∠1 and ∠3 are supplementary by the definition of supplementary.


kotegsom [21]3 years ago
6 0
1. Linear Pair Postulate
2. MAngle 3
3.Angle 3
4.Angle Congruence Postulate

Hope this helps!
-Soul
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Ira Lisetskai [31]

Answer:

5 2/3

Step-by-step explanation:

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Kate watched a beetle and spider on the sidewalk. The beetle crawled 5/8 of a yard and the spider crawled 3/8 of a yard. How muc
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2/8 or 1/4 of a yard.

Step-by-step explanation:

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Read 2 more answers
A jug has 1 litre of 10% strength cordial. How much pure cordial needs to be added to make the strength 20%?
garik1379 [7]

Answer:

The volume or amount of pure cordial to be added to the solution to make the strength 20% is 125 ml

Step-by-step explanation:

The given parameters, are;

The volume of cordial in the jug = 1 litre

The percentage strength of the cordial = 10%

The proportion of the cordial that contains pure cordial = 0.1

Therefore, the volume of pure cordial in the jug = 0.1 × 1 = 0.1 × 1000 ml = 100 ml

The volume of the solvent = The volume of the solution -  The initial volume of pure cordial

∴ The volume of the solvent = 1000 ml - 100 ml = 900 ml

To increase the concentration of the cordial to 20% is given by the relation;

x/(x+900) = 0.2

Where;

x = The total volume of the pure cordial to be added to the pure solvent

Solving, gives;

x = 0.2×(x+900) = 0.2·x + 180

x -0.2·x = 180

0.8·x = 180

x = 180/0.8 = 225 ml

The total volume of the pure cordial to be added to the pure solvent = x = 225 ml

Therefore, the volume of pure cordial to be added to the initial volume of pure cordial in the solution, which is 100 ml, is therefore given as follows;

The volume or amount of pure cordial to be added = 225 ml - 100 ml = 125 ml.

The volume or amount of pure cordial to be added = 125 ml

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