Which of the following is an example of a lever? knife ramp pencil sharpener wheelbarrow

a load of 800 newton is lifted by an effort of 200 Newton. if the load is placed at a distance of 10 cm from the fulcrum. what w

nataly862011 [7]

Answer:

40 cm

Explanation:

We are given that

Load=800 N

Effort=200 N

Load distance=10 cm

We have to find the effort distance.

We know that

$load\times load\;distance=Effort\times effort\;distance$

Using the formula

$800\times 10=200\times effort\;distance$

Effort distance= $\frac{800\times 10}{200}$

Effort distance= $\frac{8000}{200}$

Effort distance=40 cm

Hence, the effort distance will be 40 cm.

7 0

3 years ago

A photon of wavelength 7.33 pm scatters at an angle of 157° from an initially stationary, unbound electron. What is the de Brogl

Ann [662]

Answer:

4.63 p.m.

Explanation:

The problem given here can be solved by the Compton effect which is expressed as

$\lambda^{'}-\lambda=\frac{h}{m_e c}(1-cos\theta)$

here, $\lambda$ is the initial photon wavelength, $\lambda^{'}$ is the scattered photon wavelength, h is he Planck's constant, $m_e$ is the free electron mass, c is the velocity of light, $\theta$ is the angle of scattering.

Given that, the scattering angle is, $\theta=157^{\circ}$

Putting the respective values, we get

$\lambda^{'}-\lambda=\frac{6.626\times 10^{-34} }{9.11\times 10^{-31}\times 3\times 10^{8} } (1-cos157^\circ ) m\\\lambda^{'}-\lambda=2.42\times 10^{-12} (1-cos157^\circ ) m\\\lambda^{'}-\lambda=2.42(1-cos157^\circ ) p.m.$

Therfore,

$\lambda^{'}-\lambda=4.64 p.m.$

Here, the photon's incident wavelength is $\lamda=7.33pm$

So,

$\lambda^{'}=7.33+4.64=11.97 p.m$

From the conservation of momentum,

$\vec{P_\lambda}=\vec{P_{\lambda^{'}}}+\vec{P_e}$

here, $\vec{P_\lambda}$ is the initial photon momentum, $\vec{P_{\lambda^{'}}}$ is the final photon momentum and $\vec{P_e}$ is the scattered electron momentum.

Expanding the vector sum, we get

$P^2_{e}=P^2_{\lambda}+P^2_{\lambda^{'}}-2P_\lambda P_{\lambda^{'}}cos\theta$

Now expressing the momentum in terms of De-Broglie wavelength

$P=h/\lambda$ and putting it in the above equation we get,

$\lambda_{e}=\frac{\lambda \lambda^{'}}{\sqrt{\lambda^{2}+\lambda^{2}_{'}-2\lambda \lambda^{'} cos\theta}}$

Therfore,

$\lambda_{e}=\frac{7.33\times 11.97}{\sqrt{7.33^{2}+11.97^{2}-2\times 7.33\times 11.97\times cos157^\circ }} p.m.\\\lambda_{e}=\frac{87.7401}{18.935} = 4.63 p.m.$

This is the de Broglie wavelength of the electron after scattering.

8 0

4 years ago

For each pair of vehicles, choose the vehicle that would experience the greatest force of impact in a collision. Type your answe

velikii [3]

Answer:

I need help on this tooo

Explanation:

8 0

3 years ago

Help!!

emmainna [20.7K]

Answer:

Mistakes, chaos theory.

Explanation:

Weather forecast refers to the application of technology and science in predicting what the condition's of an atmosphere would be at a particular time in a given location. Keyword here is "Predicting."

To accurately "predict" the weather, observation data needs to be collected from weather stations across the world. The data collected from the stations are too complex such that they can only be processed by supercomputers.

It is important to note that supercomputers used to predict weather are liable to make mistakes because the enormous challenge of weather forecasting is more than their capabilities.

In addition, there is a concept known as chaos theory. It explains how very small changes in initial weather conditions can change the final results. No thanks to chaos, meteorologists would not be able to predict weather accurately.

This is the reason why the world still suffers from the incidence of surprise rain, storms and other weather events that could be devastating.

4 0

3 years ago

8 The diagram shows four identical spheres placed between two wooden blocks on a ruler.

enyata [817]

The diameter of the sphere is 2cm.

<h3>How to calculate the diameter?</h3>

From the diagram, the first sphere on the ruler is at 4cn and the last sphere is at 12cm.

Therefore, the length will be:

= 12 - 4.

= 8cm

The diameter of one sphere will be:

= Length / 4

= 8/4

= 2

Therefore, the diameter of the sphere is 2cm.

Note that the second question wasn't found online.

Learn more about diameter on:

brainly.com/question/358744

#SPJ1

8 0

2 years ago