Answer:
q = 2.65 10⁻⁶ C
Explanation:
For this exercise we use Coulomb's law
F =
In this case they indicate that the load is of equal magnitude
q₁ = q₂ = q
the force is attractive because the signs of the charges are opposite
F =
q =
we calculate
q =
q = Ra 7 10-12
q = 2.65 10⁻⁶ C
Both the total momentum and the total kinetic energy are conserved
Explanation:
- In a collision between two or more objects, if there are no external forces acting on the system (isolated system), the total momentum of the objects is always conserved. This is called principle of conservation of momentum, and can be written as follows:
where
m, M are the masses of the two objects
u, U are the initial velocities of the two objects
v, V are the final velocities of the two objects
- The total kinetic energy, however, is not always conserved. In fact, we have two types of collision:
1) In a perfectly elastic collision, the total kinetic energy of the objects is conserved. This means that we can write the following equation:
2) In an inelastic collision, the total kinetic energy of the object is NOT conserved. This means that part of the total kinetic energy is "lost", converted into other forms of energy (mainly thermal energy, due to the presence of frictional forces within the system). The most extreme case is called perfectly inelastic collision, in which the two objects stick together after the collision, and there is the maximum loss of kinetic energy.
Learn more about collisions:
brainly.com/question/13966693#
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