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maw [93]
3 years ago
6

How much greater is the light-collecting area of a 6-meter telescope than a 3-meter telescope? How much greater is the light-col

lecting area of a 6- telescope than a 3- telescope?
A) two times
B) four times
C) six times
Physics
1 answer:
vovikov84 [41]3 years ago
7 0

Answer:

B) four times

Explanation:

Area of 6 meter telescope

A_1=\pi \frac{D^2}{4}\\\Rightarrow A_1=9\pi

Area of 3 meter telescope

A_2=\pi \frac{D^2}{4}\\\Rightarrow A_1=2.25\pi

Dividing the equations we get

\frac{A_1}{A_2}=\frac{9\pi}{2.25\pi}\\\Rightarrow A_1=4A_2

Hence, the 6-meter telescope has 4 times the light-collecting area of the 3-meter telescope.

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How do the earth's physical features affect people's activities?
masya89 [10]

Answer:

d.all of the above

Explanation:

The physical feature of the planet Earth affect people's activities in the following manner -  

  • Choice of Occupation  - the process of occupation is completely a land depended process , hence any changes on the physical features of Earth , like the climate , temperature , rain etc , will hinder the occupations process .
  • Method of transportation - it is also a Climate dependent process , so any change in climate may obstruct the transportation facility .
  • Recreational activities - also depends on the physical feature of the planet Earth .
4 0
3 years ago
The magnetic field at 8 cm distance from a long straight wire, carrying is 0.2x10^-5 T. How much is the electric current in the
FrozenT [24]

Answer:

The electric current in the wire is 0.8 A

Explanation:

We solve this problem by applying the formula of the magnetic field generated at a distance by a long and straight conductor wire that carries electric current, as follows:

B=\frac{2\pi*a }{u*I}

B= Magnetic field due to a straight and long wire that carries current

u= Free space permeability

I= Electrical current passing through the wire

a  = Perpendicular distance from the wire to the point where the magnetic field is located

Magnetic Field Calculation

We cleared (I) of the formula (1):

I=\frac{2\pi*a*B }{u} Formula(2)

B=0.2*10^{-5}  T = 0.2*10^{-5} \frac{weber}{m^{2} }

a  =8cm=0.08m

u=4*\pi *10^{-7} \frac{Weber}{A*m}

We replace the known information in the formula (2)

I=\frac{2\pi*0.08*0.2*10^{-5}  }{4\pi *10x^{-7} }

I=0.8 A

Answer: The electric current in the wire is 0.8 A

4 0
3 years ago
A toy spacecraft is launched directly upward. When the toy reaches its highest point, a spring is released and the toy splits in
Murljashka [212]

Answer:

A

Explanation:

Momentum conservation will cause 0.08kg to move to the west (opposite of 0.02 kg).

and because both are at the same height above the ground, they will take the same time to reach the ground.

The speed of 0.08kg will be less than 0.02 kg, let v be the speed of 0..02kg, then speed of 0.08kg V is

0.02v - (0.08)V = 0

V = 0.02 v/ 0.08 = v/4

The speed of 0.08 kg = v/4

The speed of 0.08 kg is less than 0.02kg.

So 0.02kg strikes the ground farther from the launch point than does the 0.08 kg

8 0
3 years ago
Why there is tides in sea and ocean
AleksandrR [38]

Answer:

<em>    Tides are the rise and fall of sea levels. Tides occur due to the gravitational forces exerted on the Earth by moon, and to a lesser extent, the sun. That's why tides occur in ocean or sea.</em>

Hope this helps

:)

7 0
4 years ago
A wheel has a rotational inertia of 16 kgm2. Over an interval of 2.0 s its angular velocity increases from 7.0 rad/s to 9.0 rad/
german

Answer:

<h2>128.61 Watts</h2>

Explanation:

Average power done by the torque is expressed as the ratio of the workdone by the toque to time.

Power = Workdone by torque/time

Workdone by the torque = \tau \theta = I\alpha * \theta

I is the rotational inertia = 16kgm²

\theta = angular\ displacement

\theta = 2 rev = 12.56 rad

\alpha \ is \ the\ angular\ acceleration

To get the angular acceleration, we will use the formula;

\alpha = \frac{\omega_f^2- \omega_i^2}{2\theta}

\alpha = \frac{9.0^2- 7.0^2}{2(12.54)}\\\alpha = 1.28\ rad/s^{2}

Workdone by the torque = 16 * 1.28 * 12.56

Workdone by the torque = 257.23 Joules

Average power done by the torque = Workdone by torque/time

=  257.23/2.0

= 128.61 Watts

8 0
3 years ago
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