Magnitude of acceleration = (change in speed) / (time for the change) .
Change in speed = (end speed) - (start speed)
= (2 m/a) - (8 m/a) = -6 m/a .
Time for the change = (end time) - (start time)
= (13 sec) - (10 sec) = 3 sec .
Magnitude of acceleration = (-6 m/a) / (3 sec)
= -2 m/a per second .
(That's the best I can do with the ambiguous units.
What unit of speed is 'm/a' ? Is that "miles per afternoon" ?)
An unbalanced net force must be applied .option B.hope it helps plz mark as brainliest
Answer:
Magnitude of Vector = 79.3
Explanation:
When a vector is resolved into its rectangular components, it forms two vector components. These components are named as x-component and y-component, they are calculated by the following formulae:
x-component of vector = (Magnitude of Vector)(Cos θ)
y-component of vector = (Magnitude of Vector)(Sin θ)
where,
θ = angle of the vector with x-axis = 27°
Therefore, using the values in the equation of y-component, we get:
36 = (Magnitude of Vector)(Sin 27°)
Magnitude of Vector = 36/Sin 27°
<u>Magnitude of Vector = 79.3</u>
Answer:
Explanation:
KE = ½mv²
KE = ½(0.30)44²
KE = 290 J rounded to 2 s.d.