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son4ous [18]
3 years ago
9

Second and third class levers are differentiated by __________.

Physics
2 answers:
ira [324]3 years ago
5 0

Answer:

i think it is b

hope this helps

Explanation:

azamat3 years ago
3 0

Answer: B

Explanation:the load in the second class lever is found in between the effort and the fulcrum

While in third class lever effort is found in between load and fulcrum

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Human are eurkaryotic.  Eukaryotes are organisms that have cells with a nucleus.  Prokayotes are cells without a nucleus.  Protists are eukaryotic but they are usually single cellular. Also, human are not fungus.  Fungus cannot move and have to get food from its surrounding area.
3 0
3 years ago
A young woman with normal distant vision has a 10.0% ability to accommodate (that is, increase) the lens strength (a.k.a, lens p
Kipish [7]

Answer:

20.0 cm

Explanation:

Here is the complete question

The normal power for distant vision is 50.0 D. A young woman with normal distant vision has a 10.0% ability to accommodate (that is, increase) the power of her eyes. What is the closest object she can see clearly?

Solution

Now, the power of a lens, P = 1/f = 1/u + 1/v where f = focal length of lens, u = object distance from eye lens and v = image distance from eye lens.

Given that we require a 10 % increase in the power of the lens to accommodate the image she sees clearly, the new power P' = 50.0 D + 10/100 × 50 = 50.0 D + 5 D = 55.0 D.

Also, since the object is seen clearly, the distance from the eye lens to the retina equals the distance between the image and the eye lens. So, v = 2.00 cm = 0.02 m

Now, P' = 1/u + 1/v

1/u = P'- 1/v

1/u = 55.0 D - 1/0.02 m

1/u = 55.0 m⁻¹ - 1/0.02 m

1/u = 55.0 m⁻¹ - 50.0 m⁻¹

1/u = 5.0 m⁻¹

u = 1/5.0 m⁻¹

u = 0.2 m

u = 20 cm

So, at 55.0 dioptres, the closet object she can see is 20 cm from her eye.

8 0
2 years ago
A bowling ball has a mass of 7.2 kg and a weight of 70.6 N. It moves down the bowling alley at 1 m/s and strikes a pin with a fo
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4 0
3 years ago
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This table shows four examples of experiments.
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Answer

32000

Explanation:

120394

5 0
3 years ago
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The earth spins on its axis once a day and orbits the sun once a year (365 1/4 days). Determine the average angular velocity (in
lubasha [3.4K]

Answer:

Given that

The earth spins on its axis once a day and orbits the sun once a year (365 1/4 days)

a)

When earth spins on its axis

We know that earth take 1 day to complete one revolution around its own axis.

T= 1 day = 24 hr = 24 x 3600 s

T=86400 s

We know that

T=2π/ω

ω= 2π/T

ω= 2π/86400

ω=7.27 x 10⁻5 rad/s

b)

When earth revolve around earth

T =365 1/4 days = 365.25 days

T= 365.24 x 86400 s

T=31557600

We know that

T=2π/ω

ω= 2π/T

ω= 2π/31557600

ω=1.99 x 10⁻⁷ rad/s

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3 years ago
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