The power that heat pump draws when running will be 6.55 kj/kg
A heat pump is a device that uses the refrigeration cycle to transfer thermal energy from the outside to heat a building (or a portion of a structure).
Given a heat pump used to heat a house runs about one-third of the time. The house is losing heat at an average rate of 22,000 kJ/h and if the COP of the heat pump is 2.8
We have to determine the power the heat pump draws when running.
To solve this question we have to assume that the heat pump is at steady state
Let,
Q₁ = 22000 kj/kg
COP = 2.8
Since heat pump used to heat a house runs about one-third of the time.
So,
Q₁ = 3(22000) = 66000 kj/kg
We known the formula for cop of heat pump which is as follow:
COP = Q₁/ω
2.8 = 66000 / ω
ω = 66000 / 2.8
ω = 6.66 kj/kg
Hence the power that heat pump draws when running will be 6.55 kj/kg
Learn more about heat pump here :
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Answer:
False
Explanation:
10 is not the same as -10 but if -10 is the absolute value they would be the same
Give me brainllest
Answer:
Acclⁿ = 18m/s² .
Explanation:
Mass = 10 kg
Frictional force is acting in opposite dirⁿ . Therefore the net force will be ,
=> F_net = 200N - Fricⁿ force
=> m * a_net = 200N - u mg
=> 10kg *a_net = 200N - 0.2*10*10
=> a_net = 180/10 m/s²
=> a_net = 18m/s²
Answer:
The answer would be A (distance traveled in a certain amount of time) !! I did the test ;w;
