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zalisa [80]
3 years ago
7

Can anyone answer this​

Physics
2 answers:
Usimov [2.4K]3 years ago
7 0

Answer:

1 True

2 False

3 False

4 True

5 True

Hope that helps you

please mark brainliest

please follow

Yuki888 [10]3 years ago
5 0

Answer:

A. true

B. false

C. false

D. ?????

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Which explains what a velocity time graph would look like with no acceleration?
ololo11 [35]
Straight line with no slope
7 0
2 years ago
Read 2 more answers
Two blocks collide on a frictionless surface. After the collision, the blocks sticktogether. Block A has a mass M and is initial
jasenka [17]

Answer:

ΔPa = –2/3Mv

ΔPb = 2/3Mv

ΔPc = Mv.

Explanation:

See attachment below please.

5 0
2 years ago
Assuming a vertical trajectory with no drag, derive the applicable form of the rocket equation for this application
VARVARA [1.3K]

Answer:

The vertical trajectory is governed by Ordinary Differential Equation.

Time derivatives of each state variables.

d(d)/dt = v, d(m)/dt = -d(m-fuel)/dt, d(v)/dt = F/m.

Where V is velocity positive upwards, t is time, m is mass, m-fuel is fuel mass, F is Total force, positive upwards.

Therefore,

F = -mg - D + T, If V is positive and

F = -mg + D - T, If T is negative.

D is drag and the questions gave it as zero.

Explanation:

The two sign cases in derivative equations above are required because F is defined positive up, so the drag D and thrust T can subtract or add to F depending in the sign of V . In contrast, the gravity force contribution mg is always negative. In general, F will be some function of time, and may also depend on the characteristics of the particular rocket. For example, the T component of F will become zero after all the fuel is expended, after which point the rocket will be ballistic, with only the gravity force and the aerodynamic drag force being p

8 0
3 years ago
A bicycle wheel rotates at a constant 25 rev/min. What is true about its angular acceleration?
Nostrana [21]

Answer:

The angular acceleration is zero

Explanation:

When an object is in rotational motion, it has a certain angular velocity, which is the rate of displacement of its angular position.

This angular velocity can change or remain constant - this is given by the angular acceleration, which is:

\alpha =\frac{\Delta \omega}{\Delta t}

where

\Delta \omega is the change in angular velocity

\Delta t is the time elapsed

Therefore, the angular acceleration is the rate of change of angular velocity.

In this problem, the bicycle rotates at a constant angular velocity of

\omega=25 rev/min

This means that the change in angular velocity is zero:

\Delta \omega=0

And so, that the angular acceleration is zero:

\alpha=0

8 0
3 years ago
A satellite is in a circular orbit around a planet. A second satellite is placed in a different circular orbit that is farther a
irinina [24]

The speed of the second satellite is less than the speed of the first satellite.

<h3>What is speed?</h3>

The speed of any moving object is the ratio of the distance covered and the time taken to cover that distance.

Given is a satellite is in a circular orbit around a planet. A second satellite is placed in a different circular orbit that is farther away from the same planet.

When the distance from the center of the orbit increases, the time to complete the orbit will be greater.

Thus, the speed of the second satellite is less than the speed of the first satellite.

Learn more about speed.

brainly.com/question/7359669

#SPJ1

3 0
2 years ago
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