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Svet_ta [14]
3 years ago
14

How can you solve for the unknown in each equation

Mathematics
1 answer:
creativ13 [48]3 years ago
3 0

Answer:

it depends on the equation on what your solving

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If someone can please answer the question in the picture thatd be great
Ann [662]

Answer:

≈ 20.8 ft

Step-by-step explanation:

A right triangle is formed between the wall, the ground and the ladder.

The ladder is the hypotenuse , the wall and ground are the legs.

let h be the height of the wall, then using Pythagoras' identity

h² + 33² = 39²

h² + 1089 = 1521 ( subtract 1089 from both sides )

h² = 432 ( take the square root of both sides )

h = \sqrt{432} ≈ 20.8 ft ( to the nearest tenth )

5 0
3 years ago
The graph shows which inequality? The equation of the boundary line is y = –x + 4. y –x + 4 y ≥ –x + 4
DaniilM [7]

Answer:

y≤-x+4

Step-by-step explanation:

x intercept =4

y intercept=4

the shaded area under the solid line because it is greater than or equal

8 0
3 years ago
Mr. and Mrs. Jones are a newlywed couple with no children. They have an estimated monthly budget of $3,878. What is the minimum
KatRina [158]

Answer:

$1939

Step-by-step explanation:

easy, just half the total need!

3 0
3 years ago
Read 2 more answers
A rock was thrown from the top of a cliff such that its distance above sea level was given by s(t)= at² + bt + c, where t is the
frutty [35]

Answer:

<h2>a) a = -3, b = 18, c = 48; </h2><h2>s(t) = -3t²+18t+48</h2><h2>b) 48m</h2><h2>c) 8secs</h2>

Step-by-step explanation:

The question is incomplete. Here is the complete question.

'A rock was thrown from the top of a cliff such that its distance above sea level was given by s(t)=at²+bt+c, where t is the time in seconds after the rock was released. After 1 second the rock was 63 m above sea level, after 2 seconds 72 m, and after 7 seconds 27 m. a. Find a, b and c and hence an expression for s(t). b. Find the height of the cliff. c. Find the time taken for the rock to reach sea level.'

Given the equation of the distance modelled as s(t)=at²+bt+c

If after 1 second the rock was 63 m, then 63 = a+b+c

If after 2 seconds, the distance was 72 m then 72 = 4a+2b+c

Also if after 7 seconds, the distance is 27 m, then 27 = 49a+7b+c

i) Solving the 3 equations simultaneously to get a, b and c we have;

a+b+c = 63 ... 1

4a+2b+c = 72 ...2

49a+7b+c = 27 ...3

Subtracting 2 from 1 and 3 from 2 we will generate 2 new equations as shown;

eqn 2- eqn1: 3a + b = 9...4

eqn 3- eqn 2: 45a + 5b = -45

eqn 3- eqn 2: 9a+b = -9 ... 5

solving 4 and 5 simultaneously

3a + b = 9 ...4

9a+b = -9 ... 5  

Taking the difference of 4 and 5 we have

6a - -9-9

6a = -18

a = -3

substituting a = -3 into equation 4 to get b we have;

3(-3)+b = 9

-9 + b = 9

b = 9+9

b = 18

substituting a = -3 and b = 18 into equation 1 to get c we have;

-3+18+c = 63

15+c = 63

c = 48

a = -3, b= 18 and c = 48

The distance function will be s(t) = -3t²+18t+48

ii) If the height of the cliff is modelled by the equation  s(t)=at²+bt+c

The height of the cliff is at when t = 0

s(0) = -3(0)²+18(0)+48

s(0) = 48m

The height of the cliff is 48m

iii) At the sea level, the height of the rock will be 0m, substituting this into the modeled equation for the height to get the time we have;

s(t)=at²+bt+c

0 = -3t²+18t+48

3t²-18t-48 = 0

t² - 6t - 16 =0

t² - 8t+2t - 16 = 0

t(t-8)+2(t-8) = 0

(t+2)(t-8) = 0

t = -2 or 8

Taking the positive value of the time, t = 8secs

Time taken for the rock to reach sea level is 8secs

7 0
3 years ago
Write an equation in slope intercept form for the line that passes through (-3,-1) and
ahrayia [7]

Step-by-step explanation:

The equation is y = -x - 4.

8 0
2 years ago
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