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Svet_ta [14]
4 years ago
14

How can you solve for the unknown in each equation

Mathematics
1 answer:
creativ13 [48]4 years ago
3 0

Answer:

it depends on the equation on what your solving

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What is the answer to this.. 8(4n+13)=6n ...i need help
ollegr [7]
8(4n + 13) = 6n
Use distributive property so :8 (4n) = 32n and 8(13) = 104
32n + 104 = 6n
Subtract 32n from each side and you will get:
104 = 26n
then you divide each side by 26 and your answer will be:
n = 4
3 0
3 years ago
Read 2 more answers
What is the value of x in the equation 3x-4y =65, when y = 4? i will gift brainliest
Elenna [48]

Answer:

3x-4y=65

3x=65+4y

x=(65+4y)/3, when y=4

x=(65+4*4)/3

x=(65+16)/3

x=81/3

x=27

5 0
3 years ago
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Please help how do I do this ??
AleksAgata [21]
For 10 here is the answer and for 9 i’ll reply to my comment

3 0
3 years ago
841 rounded to the nearest 10 and 100
LUCKY_DIMON [66]

Answer:

rounded to the nearest 10 is 840

rounded to the nearest 100 is 800

Step-by-step explanation:

6 0
3 years ago
A particular telephone number is used to receive both voice calls and fax messages. suppose that 20% of the incoming calls invol
Phoenix [80]

Answer:

0.1091 or 10.91%

Step-by-step explanation:    

We have been given that a particular telephone number is used to receive both voice calls and fax messages. suppose that 20% of the incoming calls involve fax messages and consider a sample of 20 calls. We are asked to find the probability that exactly 6 of the calls involve a fax message.  

We will use Bernoulli's trials to solve our given problem.

P(X=x)=^nC_x\cdot P^x(1-P)^{n-x}

P(X=6)=^{20}C_6\cdot (0.20)^6(1-0.20)^{20-6}

P(X=6)=\frac{20!}{6!(20-6)!}\cdot (0.20)^6(0.80)^{14}

P(X=6)=\frac{20!}{6!(14)!}\cdot (0.000064)(0.04398046511104)

P(X=6)=38760\cdot (0.000064)(0.04398046511104)

P(X=6)=0.1090997009730

P(X=6)\approx 0.1091\\

Therefore, the probability that exactly 6 of the calls involve a fax message would be approximately 0.1091 or 10.91%.

4 0
3 years ago
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