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4 years ago

13

The probability that a student graduating from Suburban State University has student loans to pay off after graduation is . If t

wo students are randomly selected from this university, what is the probability that neither of them has student loans to pay off after graduation?

1 answer:

xenn [34]4 years ago

3 0

Answer:

Probability that the randomly selected two students both have no loans to pay = 0.09

Step-by-step explanation:

Probability that a student has a loan to pay is 0.7, hence probability that a student has no loan to pay is

1-0.7 = 0.3

Probability that the randomly selected two students both have no loans to pay = 0.3 × 0.3 = 0.09

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3 years ago

Which of the following is the quotient of b and a?

vlabodo [156]

$\bf 19^{\frac{7}{4}}\cdot \sqrt[a]{19^b}=19^{\frac{5}{2}}\sqrt{19}\\\\
-----------------------------\\\\
a^{\frac{{ n}}{{ m}}} \implies \sqrt[{ m}]{a^{ n}} \qquad \qquad
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thus\qquad 19^{\frac{7}{4}}\cdot 19^{\frac{b}{a}}=19^{\frac{5}{2}}\cdot 19^{\frac{1}{2}}\implies 19^{\frac{7}{4}+\frac{b}{a}}=19^{\frac{5}{2}+\frac{1}{2}}
\\\\\\
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$\bf 19^{\frac{7}{4}+\frac{b}{a}}=19^{\frac{6}{2}}\implies 19^{\frac{7}{4}+\frac{b}{a}}=19^3\impliedby 
\begin{array}{llll}
\textit{same base, thus}\\
\textit{exponents must be the same}
\end{array}
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3 years ago

In a Pew Research Center poll of 745 randomly selected adults, 589 said that it is morally wrong to not report all income on tax

Nikolay [14]

Answer:

a

The null hypothesis is $H_o : p = 0.75$

The alternative hypothesis is $H_a : p \ne 0.75$

b

$t = 2.51$

c

$p-value = 0.01207$

d

There no sufficient evidence to conclude that 75% of adults say that it is morally wrong to not report all income on tax returns

Step-by-step explanation:

From the question we are told that

The sample size is $n = 745$

The number that said it is morally wrong is $k = 589$

The level of significance is $\alpha = 0.01$

The population proportion is $p = 0.75$

Generally the sample proportion is mathematically represented as

$\r p = \frac{k}{n}$

=> $\r p = \frac{589}{745}$

=> $\r p = 0.79$

The null hypothesis is $H_o : p = 0.75$

The alternative hypothesis is $H_a : p \ne 0.75$

The standard error is mathematically represented as

$SE = \sqrt{\frac{p(1-p)}{n} }$

=> $SE = \sqrt{\frac{0.75(1-0.75)}{745} }$

=> $SE =0.0159$

Generally the test statistics is mathematically represented as

$t = \frac{\r p - p }{SE}$

=> $t = \frac{0.79 - 0.75 }{0.0159}$

=> $t = 2.51$

Generally the p-value is mathematically represented as

$p-value = 2 * P(Z > 2.51)$

From the the z-table

$P(Z > 2.51) = 0.0060366$

=> $p-value = 2 * 0.0060366$

=> $p-value = 0.01207$

From the calculation $p-value >\alpha$

Hence we fail to reject the null hypothesis

Thus there no sufficient evidence to conclude that 75% of adults say that it is morally wrong to not report all income on tax returns

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3 years ago