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s2008m [1.1K]
3 years ago
11

Use a definition, postulate, or theorem to find the value of x in the figure described.

Mathematics
1 answer:
Yuri [45]3 years ago
5 0
The Definition of Linear Pair states that both ∠ABC and ∠CBD are equal to 180 degrees. In the question, this tells you that 
m∠ABC and m∠CBD = (3x − 6). 
So, you're equation should be (3x - 6) + (3x - 6) = 180. 
You would then solve to get 6x - 12 = 180, 6x = 192, x = 32
x=32, and we used the Linear Pair Theorem (C)

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Which counterexample shows that the conjecture "All animals that can fly are birds" is false?
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It seems like you forgot to post the answer choices. However, bats are one animal where they can fly but they aren't birds. So this is one counter-example to prove the claim false. Another example would be any flying insects. 
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Beth buys 5 gallons of tea for a party. If each serving is 1 cup how kany servings will there be at the party
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Answer:

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Step-by-step explanation:

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3 years ago
The average amount of time that students use computers at a university computer center is 36 minutes with a standard deviation o
frosja888 [35]

Answer:

2119 students use the computer for more than 40 minutes. This number is higher than the threshold estabilished of 2000, so yes, the computer center should purchase the new computers.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 36, \sigma = 5

The first step to solve this question is finding the proportion of students which use the computer more than 40 minutes, which is 1 subtracted by the pvalue of Z when X = 40. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{40 - 36}{5}

Z = 0.8

Z = 0.8 has a pvalue of 0.7881.

1 - 0.7881 = 0.2119

So 21.19% of the students use the computer for longer than 40 minutes.

Out of 10000

0.2119*10000 = 2119

2119 students use the computer for more than 40 minutes. This number is higher than the threshold estabilished of 2000, so yes, the computer center should purchase the new computers.

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