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andreev551 [17]
3 years ago
15

Why does dividing by 10 shift each digit one place to the right?Clear

Mathematics
1 answer:
Sedbober [7]3 years ago
8 0

Answer:

D. Each digit represents 10 times its original value.

Step-by-step explanation:

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wlad13 [49]
Answer is 0. Use PEMDAS. Trust the process
6 0
3 years ago
Noreen can walk 1/3 mile in 12 minutes. What is her average speed in miles per hour?
Ksivusya [100]

Answer:

2 miles per hour

Step-by-step explanation:

12 minutes is .2 hours

1/3 divided by .2 is 1.66666667 round to nearest whole number and get 2

5 0
3 years ago
Read 2 more answers
There are two games involving flipping a coin. In the first game you win a prize if you can throw between 45% and 55% heads. In
Nina [5.8K]

Answer:

d) 300 times for the first game and 30 times for the second

Step-by-step explanation:

We start by noting that the coin is fair and the flip of a coin has a probability of 0.5 of getting heads.

As the coin is flipped more than one time and calculated the proportion, we have to use the <em>sampling distribution of the sampling proportions</em>.

The mean and standard deviation of this sampling distribution is:

\mu_p=p\\\\ \sigma_p=\sqrt{\dfrac{p(1-p)}{N}}

We will perform an analyisis for the first game, where we win the game if the proportion is between 45% and 55%.

The probability of getting a proportion within this interval can be calculated as:

P(0.45

referring the z values to the z-score of the standard normal distirbution.

We can calculate this values of z as:

z_H=\dfrac{p_H-\mu_p}{\sigma_p}=\dfrac{(p_H-p)}{\sqrt{\dfrac{p(1-p)}{N}}}=\sqrt{\dfrac{N}{p(1-p)}}*(p_H-p)>0\\\\\\z_L=\dfrac{p_L-\mu_p}{\sigma_p}=\dfrac{p_L-p}{\sqrt{\dfrac{p(1-p)}{N}}}=\sqrt{\dfrac{N}{p(1-p)}}*(p_L-p)

If we take into account the z values, we notice that the interval increases with the number of trials, and so does the probability of getting a value within this interval.

With this information, our chances of winning increase with the number of trials. We prefer for this game the option of 300 games.

For the second game, we win if we get a proportion over 80%.

The probability of winning is:

P(p>0.8)=P(z>z^*)

The z value is calculated as before:

z^*=\dfrac{p^*-\mu_p}{\sigma_p}=\dfrac{p^*-p}{\sqrt{\dfrac{p(1-p)}{N}}}=\sqrt{\dfrac{N}{p(1-p)}}*(p^*-p)>0

As (p*-p)=0.8-0.5=0.3>0, the value z* increase with the number of trials (N).

If our chances of winnings depend on P(z>z*), they become lower as z* increases.

Then, we can conclude that our chances of winning decrease with the increase of the number of trials.

We prefer the option of 30 trials for this game.

8 0
3 years ago
Ann lives 3/10 mile from school. Carlos lives 1/10 mile from school. How much farther from school does Ann live than Carlos?
sattari [20]
3/10 - 1/10 =2/10
Thats what I think
7 0
3 years ago
TanA+tanB+tanAtanB=1 If A+B=45 degree​
djyliett [7]

Answer:

See below

Step-by-step explanation:

\tan A+\tan B + \tan A.\tan B = 1\\\\ \implies \: \tan A +  \tan B =  1 -  \tan A.\tan B  \\  \\ \implies \:  \frac{\tan A +  \tan B}{ 1 -  \tan A.\tan B } = 1\\  \\ \implies \:  \tan (A +  B) = 1 \\  \\ \implies \:  \tan (A +  B) =\tan 45 \degree \\  \\ \implies \:  A +  B = 45 \degree \\  \\  thus \: proved

8 0
3 years ago
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