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ollegr [7]
3 years ago
13

what is the slope of the line that passes through the points (7,-6) and (4,-6)? write your answer in simplest form

Mathematics
1 answer:
Andrews [41]3 years ago
4 0

Answer:

<u>m = 0</u>, y = -6

Step-by-step explanation:

using point slope form :

y - y_{1} = m(x - x_{1})

y-y1=m(x-x1) ; initial point (x1,y1) = (4,-6), final point (x,y) = (7,-6).

one substituted, it should look like this:

-6--6 = m(7-4),

-6+6= m(7-4)

0 = m(7-4)

0 = 3m

0/3 = 3/3m

0 = m

m = 0/3 = 0

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Find the radius of the circle with equation x²+y²+8x+8y+28=0
galina1969 [7]
<h2>Hello!</h2>

The answer is:

Center: (-4,-4)

Radius: 2 units.

<h2>Why?</h2>

To solve the problem, using the given formula of a circle, we need to find its standard equation form which is equal to:

(x-h)^{2}+(y-k)^{2}=r^{2}

Where:

"h" and "k" are the coordinates of the center of the circle and "r" is its radius.

So, we need to complete the square for both variable "x" and "y".

The given equation is:

x^{2}+y^{2}+8x+8y+28=0

So, solving we have:

x^{2}+y^{2}+8x+8y=-28

(x^2+8x+(\frac{8}{2})^{2})+(y^2+8y+(\frac{8}{2})^{2})=-28+((\frac{8}{2})^{2})++(\frac{8}{2})^{2})\\\\(x^2+8x+16 )+(y^2+8y+16)=-28+16+16\\\\(x^2+4)+(y^2+4)=4

(x^2-(-4))+(y^2-(-4))=4

Now, we have that:

h=-4\\k=-4\\r=\sqrt{4}=2

So,

Center: (-4,-4)

Radius: 2 units.

Have a nice day!

Note: I have attached a picture for better understanding.

3 0
3 years ago
There are 5 4/11 pounds of green apples. There are 3 2/3 times as many red apples. How many pounds of red apples are there?
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Answer:

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Step-by-step explanation:

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5(n) - 2 = 3

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1. is 27

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