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insens350 [35]
2 years ago
13

Pls help!!!

Mathematics
1 answer:
Lorico [155]2 years ago
7 0

Answer:

Wouldn't the third term be 21?

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The question is:
saul85 [17]
f(x) = \sqrt{x+1} \\ y = \sqrt{x+1} \ or \ y^2 = x+1 \ or \ x = y^2 - 1 \\ Therefore, \ f^{-1}(x)=x^2 - 1

(fof^{-1})(a) = f(f^{-1}(a))=f(a^2-1) \\ =\sqrt{a^2-1+1}=\sqrt{a^2}=a \\  \\ (f^{-1}of)(a)=f^{-1}(f(a))=f^{-1}(\sqrt{a+1})= \\ (\sqrt{a+1})^2-1 = a+1-1 = a

Therefore, (fof^{-1})(a) = (f^{-1}of)(a) = a

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Bob can row 5 mph In still water. He rows directly across a river flowing at 6 mph. Using vectors, find his resultant
Ivahew [28]

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7.81mph

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Using the pythagoras theorem;

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How do you solve 6(x-3)+10=2(4x-5) step by step
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Answer:

x = 1

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5. Add 10 to both sides.

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8. Switch sides.

x = 1

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2 years ago
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