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Andreyy89
3 years ago
8

"Kyle measured the distance from his house to the library. He discovered that his measurement had a margin of error of 0.05 mile

. Which of the following could be the measured distance from his house to the library?"
a 10.6 miles

b 10 miles

c 10.65 miles

d 10.651 miles
Mathematics
2 answers:
KIM [24]3 years ago
7 0

Answer:

the answer is a

Step-by-step explanation:

Hoochie [10]3 years ago
3 0

Answer: Hello there!

We know that the margin of error in our measure is 0.05 miles.

this means that every number after the thousandths place is dominated by this error margin.

Then the answer d = 10.651 miles has that last 1, which doesn't have any value, because it contributes less than the error margin.

the right answer is c : 10.65 miles

where considering the margin of error, we can say that the distance is between 10.60 miles and 10.70 miles.

The other two answers are overly truncated.

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6 0
3 years ago
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Answer:

Therefore the  95% confidence interval is (25,707.480 < E < 26,744.920)

Step-by-step explanation:

n = 77

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standard deviation s = 2,322.32

let E = true mean

let A = test statistic

Find 95% Confidence Interval

so

let  A =  (u - E) *  (\sqrt{n}  / s)   be the test statistic

we want      P( average_l <  A  < average_u )  = 95%

look for  lower 2.5%  and the upper 97.5%  Because I think this is a 2-tail test

average_l =  -1.96  which corresponds to the 2.5%

average_u = 1.96

P(  -1.96  <  A  <  1.96)  =  95%

P(  -1.96  <  (u - E) *  (\sqrt{n}  / s)  <  1.96)  =  95%

Solve for the true mean E ok

E   <   u + 1.96* (s  / \sqrt{n})

from  -1.96  <  (u - E) *  (\sqrt{n}  / s)

E < 26,226.2 +  1.96*( 2,322.32 / \sqrt{77} )

E < 26,226.2 +  1.96*( 2,322.32 / \sqrt{77} )

E < 26,226.2 +  518.7197348105429466

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or

u - 1.96* (s  / \sqrt{n})  < E

26,226.2 -  518.7197348105429466  < E

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Answer:

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