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2 years ago

Whats the distance between (8,-3) and (4,-7)

Mathematics

1 answer:

Shtirlitz [24]2 years ago

7 0

Answer:

d=5.656854

Step-by-step explanation:

d=√ ( 4 − 8 ) 2 + (− 7 − (− 3 ) ) 2

d=√ ( − 4 ) 2 + ( − 4 ) 2

d= √ 16 + 16

d= √32

d=5.656854

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Complete the equation of the line through (-9,-9) and (-6,0)

Rudik [331]

For this case we have that by definition, the equation of the line of the slope-intersection form is given by:

$y = mx + b$

Where:

m: It is the slope of the line

b: It is the cut-off point with the y axis.

According to the data of the statement we have the following points:

$(x_ {1}, y_ {1}): (- 9, -9)\\(x_ {2}, y_ {2}): (- 6,0)$

We found the slope:

$m = \frac {y_ {2} -y_ {1}} {x_ {2} -x_ {1}} = \frac {0 - (- 9)} {- 6 - (- 9)} = \frac { 9} {- 6 + 9} = \frac {9} {3} = 3$

Thus, the equation is of the form:

$y = 3x + b$

We substitute one of the points and find b:

$0 = 3 (-6) + b\\0 = -18 + b\\b = 18$

Finally, the equation is:

$y = 3x + 18$

Answer:

$y = 3x + 18$

7 0

3 years ago

-2 (4x-9) = -18 ×=___

Dahasolnce [82]

Answer:

x = 9/2 or 4 1/2 or 4.5

Step-by-step explanation:

Divide both sides by the numeric factor on the left side, then solve. Hope this helped :)!

5 0

3 years ago

What is x2 – 6 = 16x + 30 rewritten in standard form, then factored?

AlexFokin [52]

Answer:

The standard form of quadratic equation is $x^2-16x-36=0$

The factored form of $x^2-16x-36=0$ is $(x+2)(x-18)=0$

Step-by-step explanation:

Given equation $x^2-6=16x+30$

We have to write in standard form and then factorize the given equation.

The standard form for a general quadratic equation is given as $ax^2+bx+c=0$

Consider $x^2-6=16x+30$

Taking all terms to left side, we have,

$x^2-6-16x-30=0$

Adding like terms, we have,

$x^2-16x-36=0$

Now we will factorize it.

We will solve the quadratic equation $x^2-16x-36=0$ using middle term splitting method,

-16x can be written as -18x+2x

$x^2-16x-36=0$ becomes

$\Rightarrow x^2-18x+2x-36=0$

Taking x common from first two terms and 2 common from last two terms we have,

$\Rightarrow x(x-18)+2(x-18)=0$

$\Rightarrow (x+2)(x-18)=0$

Thus, the factored form of $x^2-16x-36=0$ is $(x+2)(x-18)=0$

4 0

2 years ago

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Determine the exact values of the six trigonometric functions of the real number t

NeTakaya

Di uh e u dhehrrvhrhrhrhrgr u ej

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3 years ago

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For an angle θ with the point (−5, −12) on its terminating side, what is the value of cosine?

viva [34]

Answer:

option C. $-\frac{5}{13}$

Step-by-step explanation:

we have that

The point (-5,-12) belong to the III quadrant

The value of the cosine is negative

Applying the Pythagoras Theorem

Find the value of the hypotenuse

$h^{2}=5^{2}+12^{2}\\ h^{2} =25+144\\ h^{2}=169\\h=13\ units$

The value of cosine of angle θ is the ratio between the side adjacent to angle θ and the hypotenuse

$cos(\theta)=-\frac{5}{13}$

8 0

3 years ago