The answer would c & d in this case
This one is the Law of Sines again.
The Law of Sines relies on the standard labeling of triangle ABC with vertices A, B, and C and respective opposite sides of a, b and c. Then
Here we have A=150 degrees (opposite side a), b= 10 cm and B = 12 degrees. We seek a.
So we need the first equation of the Law of Sines:
Answer:
Honor students have a probability of 43% to non-honor students 25%.
Step-by-step explanation:
Prob of honor student getting math class choice = 215/500 = 43%
Prob of non-honor student getting math class choice = 125/500 = 25%
Answer:
no
Step-by-step explanation:
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Assume that the data for both movies and basketball games are normally distributed.
Therefore, the median and the mean are assumed equal.
The standard deviation, σ, is related to the interquartile range by
IQR = 1.35
From the data, we can say the following:
Movies:
Range = 150 - 60 = 90 (approx)
Q1 = 62 (approx), first quartile
Q3 = 120 (approx), third quartlie
Q2 (median) = 90 (approx)
IQR = Q3 - Q1 = 58
σ = IQR/1.35 = 58/1.35 = 43
Basketball:
Range = 150 - 90 = 60 approx
Q1 = 95 (approx)
Q3 = 145 (approx)
Q2 = 125 (approx)
IQR = 145 - 95 = 50
σ = 50/1.35 = 37
Test the given answers.
A. The IQRs are approximately equal, so they are not good measures of spread. This is not a good answer.
B. The std. deviation is a better measure of spread for basketball. This is not a good answer.
C. IQR is not a better measure of spread for basketball games. This is not a good answer.
D. The standard deviation is a good measure of spread for both movies and basketball. This is the best answer.
Answer: D
