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3 years ago

For any galvanic cell to operate at standard conditions,

Chemistry

1 answer:

shepuryov [24]3 years ago

4 0

Answer:

ΔG° is negative and ΔE° is positive

Explanation:

A galvanic cell produces electrical energy from spontaneous electrochemical processes.

In a galvanic cell, ∆E° is always positive since the reaction is spontaneous at room temperature.

Generally in thermodynamics, a negative value of ∆G shows a spontaneous chemical process. Hence in a galvanic cell, ΔG° is negative and ΔE° is positive.

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Please select the word from the list that best fits the definition

Nastasia [14]

Answer:

The answer is B(scale)

Explanation:

Since the question asked about a range, the scale would be the most logical answer since scales are used to measure.

6 0

4 years ago

60 POINTS

Juli2301 [7.4K]

Answer:

PBr3 - Molecule , Polar

N2H2 - Molecule , (Polar in E- form and Non- polar in Z form)

C2H2 - Molecule , Non- Polar

N2 - Molecule , Polar

NCl3 - Molecule , Polar

SiF4 - Molecule , Non- Polar

NH3 - Molecule , Polar

F - Not- Molecule (atom)

H2 - Molecule and Non- Polar

Explanation:

Molecule : these are group of two or more atoms joined by strong force of attraction.

H2 is non- polar because it is homoatomic molecule.(made up of same element)

N2 is non- polar because it is homoatomic molecule.

5 0

3 years ago

Draw a Lewis structure for [H3O]+. Show all unshared pairs and the formal charges, if any.

Montano1993 [528]

Answer: Formal Charges: Hydrogen = 0 and Oxygen = +1

Unshared Pair of electrons: Hydrogen = 0 and Oxygen = 2

Explanation:

The attachment below shows the Lewis structure and the calculations

3 0

3 years ago

Copper(II) sulfate forms a bright blue hydrate with the formula CuSO 4 ⋅ n H 2 O ( s ) . If this hydrate is heated to a high eno

Arada [10]

Answer:

The value of n in the hydrate formula is 5 , $CuSO_4.5H_2O$ .

Explanation:

$CuSO_4.nH_2O\rightarrow CuSO_4+nH_2O$

Mass of hydrate of copper sulfate = 14.220 g

Moles of hydrate of copper sulfate = $\frac{14.220 g}{(159.5+n\times 18) g/mol}$

Mass of copper sulfate after heating = 8.9935 g

Moles of copper sulfate = $\frac{8.9935 g}{159.5 g/mol}$

$\frac{14.220 g}{(159.5+n\times 18) g/mol}=\frac{8.9935 g}{159.5 g/mol}$

Solving for n, we get:

n = 5

The value of n in the hydrate formula is 5 , $CuSO_4.5H_2O$ .

5 0

4 years ago

Suppose that 5-ml containers of helium (He), neon (Ne), and argon (Ar) are at pressures of 1 atm,

Katarina [22]

The total pressure in the container after the three gases are mixed is 6 atm and the partial pressure of He is 1 atm.

<h3>What is Dalton's Law of Partial Pressure ?</h3>

According to Dalton's Law of Partial Pressure , the pressure exerted by a mixture of gas is equal to the sum of the partial pressure of the gases in the mixture.

P(total) = p₁ +p₂+p₃+.....

As the volume of the containers are same and the

n = 1*5/RT for Helium

n = 2*5 /RT for Neon

n= 3*5/RT for Argon

Mole fraction = moles of the element/Total moles

Moles fraction of Helium is

$\rm \dfrac{1*5}{1*5+2*5+3*5}$

= 1/6

Total Pressure in the container = 1 + 2 +3 = 6 atm

The partial pressure of Helium will be

=Mole fraction * Total pressure

=(1/6)*6 atm

= 1 atm , as the volume is same the temperature is same , the pressure will also be same.

To know more about Dalton's Law

brainly.com/question/14119417

#SPJ1

6 0

2 years ago