Answer: The bond between boron and hydrogen in boron trihydride is covalent bond.
Explanation:
The type of bonding between the atoms forming a compound is determined by using the electronegativity difference between the atoms. According to the pauling's electronegativity rule:
- If
, then the bond is non-polar. - If
, then the bond will be covalent. - If
, then the bond will be ionic.
We are given:
Electronegativity for boron = 2.0
Electronegativity for hydrogen = 2.1
As, 
is less than 1.7 and not equal to 0. Hence, the bond between boron and hydrogen is covalent bond.
Answer:
Water (H20)
Explanation:
When an acid combine with a base, the reaction is called neutralization and it produces salt and water. This can be seen from the reaction between HCl and NaOH as shown below:
HCl + NaOH —> NaCl + H2O
From the above equation, we see clearly that salt (NaCl) and water (H2O) are the new products form.
Answer:
The major and minor products formed from the first structure have more alkyl groups on the C═C than those formed from the second structure.
The second structure has more hydrogens attached to the β carbons than the first structure.
Explanation:
It is possible to explain the reaction based on Zaitsev’s rule that states that an elimination will normally lead to the most stable alkene as the major product. This normally translates to it giving the most substituted alkene.
The two adjacent carbons in the first molecule are secondary. That means the two products will produce a disubstituted alkene but in the second molecule just one product will be disubstituted. Thus:
The first structure has more hydrogens attached to the β carbons than the second structure. <em>FALSE</em>. If the structure has more hydrogens will produce an alkene less stable.
The major and minor products formed from the first structure have more alkyl groups on the C═C than those formed from the second structure. <em>TRUE</em>. As the first structure have more alkyl groups the product is most stable.
The major and minor products formed from the second structure have more alkyl groups on the C═C than those formed from the first structure. <em>FALSE</em>. Is the opposite of the last option.
The second structure has more hydrogens attached to the β carbons than the first structure. <em>TRUE</em>. As the second structure has more hydrogens, the alkenes produced will be less substituted being less stable.
I hope it helps!
