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Phoenix [80]
2 years ago
13

60 POINTS

Chemistry
1 answer:
Juli2301 [7.4K]2 years ago
5 0

Answer:

PBr3 - Molecule , Polar

N2H2 - Molecule , (Polar in E- form and Non- polar in Z form)

C2H2 - Molecule , Non- Polar

N2 - Molecule , Polar

NCl3 - Molecule , Polar

SiF4 - Molecule , Non- Polar

NH3 - Molecule , Polar

F - Not- Molecule (atom)

H2 - Molecule and Non- Polar

Explanation:

Molecule : these are group of two or more atoms joined by strong force of attraction.

H2  is non- polar because it is homoatomic molecule.(made up of same element)

N2 is non- polar because it is homoatomic molecule.

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Read 2 more answers
What is the pH of a 0.0288 M solution of ammonia (Kb 1.8 x 10-5)?
elena-14-01-66 [18.8K]

Answer:

10.86

Explanation:

Given that:

K_{b}=1.8\times 10^{-5}

Concentration = 0.0288 M

Consider the ICE take for the dissociation of ammonia as:

                                      NH₃    +   H₂O    ⇄     NH₄⁺ +    OH⁻

At t=0                          0.0288                             -              -

At t =equilibrium        (0.0288-x)                         x           x            

The expression for dissociation constant of ammonia is:

K_{b}=\frac {\left [ NH_4^{+} \right ]\left [ {OH}^- \right ]}{[NH_3]}

1.8\times 10^{-5}=\frac {x^2}{0.0288-x}

x is very small, so (0.0288 - x) ≅ 0.0288

Solving for x, we get:

x = 7.2×10⁻⁴  M

pOH = -log[OH⁻] = -log(7.2×10⁻⁴) = 3.14

Also,

pH + pOH = 14

So, pH = 10.86

3 0
3 years ago
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