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IgorC [24]
3 years ago
8

How do I find the chemical formula?

Chemistry
1 answer:
sladkih [1.3K]3 years ago
6 0
There are at least two ways to look at this.

Method One :
  The Zn in Zinc Cyanide belongs to valency two while the CN radical
    belongs to valency one.   As a result, you would need two CN radicals
    to bond with the Zn to make it a stable compound.  Hence the formula
    being   Zn(CN)₂

Method Two  :
   
Since the mole of zinc is 4.7 mol and that of CN is 9.5  mol then that
     means that there is twice as much moles of CN as there is Zinc  
     4.7 mol ×  2  =  9. 4 mol
.   Thus the formula would be Zn(CN)₂
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Energy to thermal energy.
sergiy2304 [10]

A hair dryer converts "electrical energy" to "thermal energy".

Option: C

<u>Explanation</u>:

The "electricity" is converted to "heat energy" in a "wire coil". Here electricity process "air" out of "the hair dryer" with the help of forced convection. Most hairdryers use a nichrome wire coil that will not oxidize when heated and allowing it to "blow" the hair dry with high temperature air which speeds up evaporation. Thus "wire heats" the "air faster", in most of the "hair dryers" the "air" is only in "the barrel" for "half of a second".

3 0
2 years ago
Which one of the following metallic element is liquid are room temperature​
cricket20 [7]

Answer:

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7 0
3 years ago
If 6.00 g of CaCl2 • 2 H2O and 5.50 g of Na2CO3 are allowed to react in aqueous solution, what mass of CaCO3 will be produced? P
Andre45 [30]

Answer:

6.00 g CaCl₂ .2H₂O /1 × 1 mol CaCl₂ .2H₂O / 147 g CaCl₂ .2H₂O × 0.04 mol CaCO₃/ 0.04 mol of  CaCl₂ .2H₂O  × 100 g CaCO₃ /  1 mole CaCO₃ = 4 g

5.50 g Na₂CO₃   /1 × 1 Na₂CO₃  / 106 g Na₂CO₃ × 0.05 mol CaCO₃/ 0.05 mol of Na₂CO₃  × 100 g CaCO₃ /  1 mole CaCO₃ = 5 g

Explanation:

Given data:

Mass of CaCl₂.2H₂O = 6.00 g

Mass of Na₂CO₃ = 5.50 g

Mass of CaCO₃ produced = ?

Solution:

Number of moles of CaCl₂.2H₂O.

Number of moles = mass/ molar mass

Number of moles = 6.00 g/ 147 g/ mol

Number of moles = 0.04 mol

Number of moles of Na₂CO₃:

Number of moles = mass/ molar mass

Number of moles = 5.50 g/ 106 g/ mol

Number of moles = 0.05 mol

Chemical equation:

CaCl₂  +  Na₂CO₃   →   CaCO₃ + 2NaCl

Now we will compare the moles of CaCO₃  with Na₂CO₃  and CaCl₂ through balanced chemical equation .

                      CaCl₂              :               CaCO₃

                             1                :                1

                       0.04               :            0.04

Mass of CaCO₃:

Mass = number of moles × molar mass

Mass = 0.04 mol× 100 g/mol

Mass = 4 g

6.00 g CaCl₂ .2H₂O /1 × 1 mol CaCl₂ .2H₂O / 147 g CaCl₂ .2H₂O × 0.04 mol CaCO₃/ 0.04 mol of  CaCl₂ .2H₂O  × 100 g CaCO₃ /  1 mole CaCO₃ = 4 g

                     Na₂CO₃            :            CaCO₃

                          1                   :                1

                       0.05               :            0.05

Mass of CaCO₃:

Mass = number of moles × molar mass

Mass = 0.05 mol× 100 g/mol

Mass = 5 g

5.50 g Na₂CO₃   /1 × 1 Na₂CO₃  / 106 g Na₂CO₃ × 0.05 mol CaCO₃/ 0.05 mol of Na₂CO₃  × 100 g CaCO₃ /  1 mole CaCO₃ = 5 g

                     

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3 years ago
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GalinKa [24]

Answer:

Electrons

Espero que te sirva

7 0
3 years ago
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