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oksano4ka [1.4K]
3 years ago
11

Calculate the mass (in grams) of silver in 10.0 grams of silver sulfide ag2s

Chemistry
1 answer:
Basile [38]3 years ago
7 0
248g Ag₂S  ----------- 216g of Ag
10g Ag₂S    ------------ x

x = 10g*216g/248g ≈ 8,71g
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Read 2 more answers
4. Calculation of theoretical yield and percent yield You balanced this reaction earlier: Mg(s) + HCl (aq) H2 (g) + MgCl2 (aq) Y
erik [133]

Answer:

Mg(s) +<em> 2</em> HCl (aq) →  H₂(g) + MgCl₂

0.415g of H₂(g) <em>-Assuming mass of Mg(s) = 10.0g-</em>

Explanation:

Balancing the reaction:

Mg(s) + HCl (aq) →  H₂(g) + MgCl₂

There are in products two atoms of H and Cl, the balancing equation is:

Mg(s) +<em> 2</em> HCl (aq) →  H₂(g) + MgCl₂

<em>Assuming you add 10g of Mg(s) -Limiting reactant-</em>

<em />

10g of Mg are (Atomic mass: 24.305g/mol):

10g × (1 mol / 24.305g) = <em>0.411 moles of Mg</em>

<em>-Theoretical yield is the amount of product you would have after a chemical reaction occurs completely-</em>

Assuming theoretical yield, as 1 mole of Mg(s) produce 1 mole of H₂(g), theoretical yield of H₂(g) is 0.411moles H₂(g). In grams:

0.411mol H₂(g) × (1.01g / mol) = <em>0.415g of H₂(g)</em>

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3 years ago
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